Let a = - 6x's square + 4x + 8, B = 4-3x-x's Square, C = 5x's Square - 7x-1, find the value of A-B + C. when calculating this problem, Xiao Ming and Xiao Jun calculate x separately Let a = - 6x square + 4x + 8, B = 4-3x-x square, C = 5x square - 7x-1, and find the value of A-B + C When Xiao Ming and Xiao Jun calculate this problem, they take different values for X, and carry out many operations. They find that the results of A-B + C are always the same. Do you think this is possible? Tell me your reasons

Let a = - 6x's square + 4x + 8, B = 4-3x-x's Square, C = 5x's Square - 7x-1, find the value of A-B + C. when calculating this problem, Xiao Ming and Xiao Jun calculate x separately Let a = - 6x square + 4x + 8, B = 4-3x-x square, C = 5x square - 7x-1, and find the value of A-B + C When Xiao Ming and Xiao Jun calculate this problem, they take different values for X, and carry out many operations. They find that the results of A-B + C are always the same. Do you think this is possible? Tell me your reasons

Maybe. Because
A-B+C=-6x²+4x+8-4+3x+x²+5x²-7x-1
A-B + C = 3, the value of A-B + C after calculation
Is a constant 3, independent of the value of X, that is to say
No matter what value you go to, the value of A-B + C is 3,
That is, their results are the same
A-B + C = - 6x square + 4x + 8 - (4-3x-x Square) + 5x square - 7x-1 = 3
When calculating the addition and subtraction of A-B + C, all the parameters with X are reduced to each other, so no matter what value x is taken, the number of A-B + C will never change, and the number of A-B + C is equal to 3
probably. because
A-B+C=-6x²+4x+8-4+3x+x²+5x²-7x-1
A-B + C = 3, the value of A-B + C is a constant 3,
In other words, the value of A-B + C is 3,
(x²+5x+6)(x²+7x+6)－3x²
(x^2+5x+6)(x^2+7x+6)-3x^2
Original formula = (x ^ 2 + 6x + 6-x) (x ^ 2 + 6x + 6 + x) - 3x ^ 2
＝(x^2+6x+6)^2 -4x^2
＝(x^2+8x+6)(x^2+4x+6)
Two polynomials are a and B. A is the square of 4x + 5x-6 if a + B is regarded as a-b
Results the answer is - 7x square + 5x-12, try to find the correct answer of a + B
Given a = 4x square + 5x-6, if a + B is regarded as A-B, the answer is - 7x square + 5x-12, then: A-B = - 7x square + 5x-12, then: B = a - (- 7x square + 5x-12) = 4x square + 5x-6 + 7x square - 5x + 12 = 11x square + 6, so: a + B = 4x square + 5x-6 + 11x square + 6 = 15x
If the square of polynomial 10-1 / 4x-5x + 9 / 4-6 + 5x is 0, then what is x =?
The title is not detailed enough, but I can tell you the method. Because the sum is zero, both items are zero
What are you writing about? I don't know which denominators are. Please enclose them. I can't try them all
3x ＾ 2-5x + 8 = x ＾ 2 + 4x + 42x ＾ 2-9x + 4 = 0 (2x-1) (x-4) = 0, then x = 1 ＾ 47; 2 or x = 4
three-fourths