x=(8－x)²－4²

x=(8－x)²－4²

There are two solutions to this problem. The first one is x = (8-x) &# 178; - 4 & # 178; X = 8 & # 178; - 16x + X & # 178; - 16x & # 178; - 17x + 48 = 0. Because △ = B & # 178; - 4ac = 289-192 = 97 > 0, so X1 = (17 + √ 97) / 2x2 = (17 - √ 97) / 2. The second one is x = (8-x) &# 178; - 4 & # 178; X = (8-x + 4) (8-x-4) X
18.9*178.178+0.49-17.8*189.18
Simple calculation
=18.9*178.178+0.49-17.8*（189+0.18）
=18.9（178.178-178）+0.49-17.8*0.18
=18.9*0.178+0.49-17.8*0.18
=0.178*（18.9-18）+0.49
=0.178*0.9+0.49
=0.6502
18.9*178.178+0.49-17.8*189.18
=3367.5642+0.49-3367.404
=3368.0542-3367.404
=0.6502
Let X and y be real numbers. If 4x ^ 2 + y ^ 2-2xy = 1, then the maximum value of 2x + y is
Let 2x + y = k, which is a linear equation. When a line is tangent to 4x ^ 2 + y ^ 2-2xy = 1, it has a maximum
Substituting the linear equation into the curve equation, we get the following results
4x^2+(k-2x)^2-2x(k-2x)=1
4x^2+k^2-4kx+4x^2-2kx+4x^2=1
Well organized
12x^2-6kx+k^2-1=0
△＝36k^2-4*12*(k^2-1)=0
12k^2=48
k=±2
It can be seen that the maximum value of 2x + y is 2
Let 4x ^ 2 + y ^ 2 = m, then 4x ^ 2 + y ^ 2-2xy = 1, M is less than or equal to 4
It can be seen from the inequality that 2x + y is less than or equal to m / 2 under the root sign of 2 *
So two roots two
You can see the other solutions of 4x ^ 2 + y ^ 2 + xy = 1. Some people have played them in great detail
X & # 178; - Y & # 178; - 5x-5y = - 12 2x + y = 0 find: x =? Y =? Solve the equations
x=2,y=-1
How to solve the square of 3 / 4x - 3 / 2 + 1 / 4 = 1
First shift the square of 3 / 4x = 1-1 / 4 + 3 / 2
Square of 3 / 4x = 9 / 4
At the same time, multiply by the square of 4 3x = 9
X = √ 3 or - √ 3
3 / 4x square = 1 + 3 / 2-1 / 4
3 / 4x square = 9 / 4
X square = 3
X = positive and negative root sign 3
How to solve (3 / 4) x & sup2; - (3 / 2) x + 1 / 4 = 1
If the denominator is removed, 3x & sup2; - 6x + 1 = 4, that is, 3x & sup2; - 6x-3 = 3 (X & sup2; - 2x-1) = 0
X & sup2; - 2x-1 = 0, so x = (2 ± √ 8) / 2 = 1 ± √ 2
Is the title wrong? I added an X.]
6-5x + X & # 178; - 16 △ x-3 / 4-x · X & # 178; + 5x + 4 / 4-x & # 178; calculation
Hello!
6-5x+x²/x²-16÷x-3/4-x·x²+5x+4/4-x²
=（x-3）(x-2)/(x+4)(x-4)÷（x-3）/(4-x)*(x+1)(x+4)/(2+x)(2-x)
=-(x-2)/(x+4) *(x+1)(x+4)/(2+x)(2-x)
=(x+1)/(x+2)
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Original formula = (X-2) (x-3) / (x + 4) (x-4) * [- (x-4) / (x-3)] * (x + 1) (x + 4) / [- (x + 2) (X-2)]
=(x-2)/(x+4)*(x+1)(x+4)/(x+2)(x-2)
=(x+1)/(x+2)
Do it yourself!
6-5x+x²/x²-16÷x-3/4-x·x²+5x+4/4-x²
=6-5x+1-16/x-3/4-x³+5x+1-x²
=-x³-x²-5x+5x+6-3/4+1+1-16/x
=-x³-x²+29/4-16/x
Given that the polynomial KX & sup2; - 6xy-8y & sup2; can be decomposed into 2 (MX + y) (x-4y), the value of K and M can be obtained
2(mx+y)(x-4y)
=2mx²+xy(2-8m)-8y²
The coefficients of polynomial corresponding degree are equal
So 2m = k2-8m = - 6
So m = 1, k = 2
Given that the real number x y satisfies the condition | 2x-3y + 1 | + (x3y + 5), the quadratic power of the formula (- 2x * y) × 6xy square is obtained
The second power of ∵ | 2x-3y + 1 | + (x + 3Y + 5) = 0
∴2x-3y+1=0
x+3y+5=0
x=-2
y=-1
The value of the square of (- 2x * y) × 6xy
=4x⁴y*(-y²)*6xy²
=-24x^5y^5
=-24*(-2)^5*(-1)^5
=-24*32
=-768
Solve the equations {x + y + 1 = 0, X & # 178; + 4Y & # 178; = 8, find the result, process!
x=-y-1,(-y-1)^2+4y^2=8,
y^2+2y+1+4y^2=8
5y^2+2y-7=0
(y-1)(5y+7)=0
Y = 1, x = - 2, or y = - 7 / 5, x = - 12 / 5
Solving 4x square-12x = 3 by formula method