Find the range of y = (X & # 178; - 1) / (X & # 178; + 1)

Find the range of y = (X & # 178; - 1) / (X & # 178; + 1)

y=（x2-1）/（x2+1）=1-2/(1+x^2)
1+x^2≥1
So 0
separate
y=1+(-2)/（x²+1）
Let t = (X & sup2; + 1)
Then (+ = 2) / T = 1
The range of t can be obtained,
So (- 2) / T can be calculated,
So the range of y = 1 + (- 2) / T can be obtained,
So the range of y = (X & sup2; - 1) / (X & sup2; + 1) can be obtained
Drawing
From 11x-9y = 6, we use the formula containing x to express y, and use the formula containing y to express X
Because 11x-9y = 6,
So - 9y = 6-11x,
So 9y = 11x-6,
So y = (11x-6) / 9;
Because 11x-9y = 6,
So 11x = 6 + 9y,
So x = (6 + 9y) / 11
y=(11x-6)/9
x=(9y+6)/11
11x-9y=6
11x=6+9y
x=(9y+6)/11
Transfer like an equation
X is y=
With X, we use y=
The formula with X denotes y
Y=(11X-6)/9
The expression with X
X=(9Y+6)/11
We are all in primary school^_^
If the quadratic trinomial x2-ax-8 (a is an integer) of X can be factorized in the range of integers, then a is______ .
X2 + 2x-8 = (x + 4) (X-2); x2-2x-8 = (x-4) (x + 2); x2 + 7x-8 = (x + 8) (x-1); x2-7x-8 = (X-8) (x + 1). So the value of a can be: ± 7, ± 2. So the answer is: ± 7, ± 2
(x+2)(x+5)=x²+7x+10.（x-2）（x-5）=x²-7x=10…… Sum up the law
X + a times x + B = x plus a + B times x plus a * B
7x-3y=-12 4x+2y=-5
It's a bit uncertain to solve the equation. What's the final answer?
7x-3y=-12 4x+2y=-5
14x-6y = - 24 12x + 6y = - 15 to get 26x = - 39 x = - 13 / 8
y=3/4
x＝9/26
y＝－83/26
The first equation is multiplied by two, and the second equation is multiplied by three
The two formulas are added left and right to get x = 9 / 26
Substituting into any equation, y = - 83 / 26
In order to factorize the quadratic trinomial x2-5x + P in the range of integers, the value of integer P can be () A. 2 b. 4 C. 6 D. innumerable
If the quadratic trinomial x2-5x + P can be decomposed, there must be: 25-4p ≥ 0, that is, P ≤ 254, which can be factorized within the range of integers. Therefore, as long as P can be decomposed into two integers, and the sum is - 5, such numbers have arrays, so there can be innumerable values of integer P. therefore, choose D
Find the range of y = x & # 178; - 1 / X & # 178; + 1
y=x^2-1/x^2+1=(x-1/x)^2+2+1=(x-1/x)^2+3
(x-1/x)≥0
y≥3
Range [3, + ∞)
What is the solution of X + 2Y + 3Z = 11 X-Y + 7x = 10 x + 3Y + 2Z = 2
X+2Y+3Z=11（1） X-Y+7z=10（2） X+3Y+2Z=2（3)
(1) If y is - 37 and Z is - 28, then x is 169
x=169
y=-37
Z = - 28: is the process real
If the quadratic trinomial x ^ 2-px-12 can be factorized in the range of integers, what values can the integer P take
In the quadratic trinomial x ^ 2-px-12, the constant term is - 12
-12 = (- 3) * 4 then - P = - 3 + 4 P = - 1
-12 = 3 * (- 4), then - P = 3-4, P = 1
-12 = (- 2) * 6 then - P = - 2 + 6 p = - 4
-12 = 2 * (- 6), then - P = 2-6, P = 4
-12 = (- 1) * 12 then - P = - 1 + 12 P = - 11
-Then p = 12-1
Y = √ - X & # 178; - 6x + 5 range is (- ∞, - 4]
No, it's obviously greater than 0. It should be [0, √ 14]
y=-x²-6x+5=--x²-6x-9+14=-(x+3)^2+14
The range is to {- infinity, 14]