How to solve this equation? The square of 2x + 6 = 7x, please use the formula: the square of B - 4ac Just like making a draft How to solve this equation? Square of 2x + 6 = 7x Please use the formula method: The square of B - 4ac It's like making a draft

How to solve this equation? The square of 2x + 6 = 7x, please use the formula: the square of B - 4ac Just like making a draft How to solve this equation? Square of 2x + 6 = 7x Please use the formula method: The square of B - 4ac It's like making a draft

2x²-7x+6=0
Δ=b²-4ac=49-48=1
According to the formula (- B ± √Δ) / 2
x1 x2=（8±1）/4
9/4 7/4
Using the formula method:
2x²-7x+6=0
a=2,b=-7,c=6
So △ = B & # 178; - 4ac = 1
x=（7±1）/4
So x = 3 / 2, x = 2
In fact, it's easier to multiply by quadratic cross of one variable.
2x² + 6 = 7x
2x² - 7x + 6 = 0
(2x - 3)(x - 2) = 0
X = 2 or x = 3 / 2
2x^2+6=7x
Move to 2x ^ 2-7x + 6 = O
a=2 b=-7 c=6
△=b^2-4ac
=(-7)×(-7)-4×2×6
=49-48
=1
The root of the equation is:
x=(-b+√△)/2a =(7+1)/4=2
perhaps
x=(-b-√△)/2a=(7-1)/4=3/2=1.5
Therefore, the root of the equation is:
X = 2 or x = 3 / 2
Transfer: 2x2-_ 7x+6=0
49-48 / 4 under the root sign of x = 7
X = (7 plus minus 1) / 4
x1=2; x2=3/2
Solving equation x (6x + 1) + 4x-3 = 2 (2x + 0.5) by formula method
To detailed process, online, etc., thank you
First of all, simplify: 6x & # 178; + X + 4x-3 = 4x + 1
6x²+x-4=0
Where a = 6, B = 1, C = 4 are substituted into the root formula x = - B ± under the root sign △ / 2A
The solution is X1 = 1 / 3, X2 = - 1 / 2
x(6x+1)+4x-3=2(2x+0.5)
The results show that 6x & # 178; + X-2 = 0
Here a = 6, B = 1, C = - 2
△＝1²－4*6*（－2)＝49>0
∴ x＝(-1±√49)/(2*6)
=(-1±7)/12
∴ x1=1/2,x2=-2/3
Factorization of 9x ^ 3-6x ^ 2Y + XY ^ 2
Factorization
9x^3-6x^2y+xy^2
=x(9x^2-6xy+y^2)
=x(3x-y)^2
Original formula = x (9x ^ 2-6xy + y ^ 2)
=x[(3x)^2-2*(3x)*y+y^2]
=x(3x-y)^2
Given that a is a root of the equation x ^ 2-3x-1 = 0 about X, then a + 1 / A=
X=a
Substituting
a²-3a-1=0
a²-1=3a
Divide both sides by A
a-1/a=3
Square on both sides
a²-2+1/a²=9
a²+1/a²=11
(a+1/a)²
=a²+2+1/a²
=11+2
=13
therefore
a+1/a=±√13
Let a be a root of the equation x ^ 2-3x-1 = 0 about X
∴a²-3a-1=0
Divide a by a to get a-3-1 / a = 0
∴a-1/a=3
∴(a+1/a)²=(a-1/a)²+4
=3²+4
=13
∴a+1/a=±√13
Using formula method to solve the equation: (1) the square of 36-x = 0, (2) the square of 4x - 12x + 9 = 0
Hurry!
(1) A = - 1, B = 36, C = 0, b-4ac = 1296-0 = 1296, 2A / - B + - root sign, b-4ac = - 2 / 36-36 = 0, er, I don't know if it's right. If it's just a matching method
(2) A = 4, B = - 12, C = 9, b-4ac = 144-144 = 0, b-4ac = 8 / 12 + - 0, x = 2 / 3 under 2A / - B + - radical
Factorization of calculation problem 9x ^ n + 1-27x ^ n = (1) original solution=
Factorization of calculation problems
9x^n+1-27x^n=
9x^n+1-27x^n
=9x^n(x-3)
Given that a is a root of the equation x ^ 2-3x + 1 = 0, find the value of A-1 / A
A is a root of the equation x ^ 2-3x + 1 = 0
a^2-3a+1=0
a+1/a=3
(a-1/a)^2=(a+1/a)^2-4=9-4=5
a-1/a=-√5,
a-1/a=√5
How to solve the equation 12x = 300-4x
We need equations
12x=300-4x
12x+4x=300
16x=300
x=300÷16
x=18.75
12x+4x=300
x=300÷16
x=18.75
12x+4x=300
16x=300
x=300/16
x=18.75
12x=300-4x
16x=300
x=18.75
12x=300-4x
12X+4X=300
16X=300
X=18.75
12x=300-4x
12x+4x=300
16x=300
16x÷16=300÷16
x=18.75
3x ^ 2-6x = - 3 (factorization)
2) X-radical 3 = 5x (radical 3-x) (factorization)
3x^2-6x+3=0
x^2-2x+1=0
(x-1)^2=0
X=1
x-√3=5x（√3 -x）
x-√3 +5x（x-√3）=0
（x-√3）（1+5x）=0
X = √ 3 or x = - 1 / 5
3(X-1)(X-1)=0
x²-2ax+a²-1
Cross multiplication:
x²-2ax+a²-1
（x-a）^2 < 1
-1 < x-a < 1
(x-a) square