Factorization of (x ^ 2-6x + 1) (x ^ 2 + X + 1) + 12x ^ 2

Factorization of (x ^ 2-6x + 1) (x ^ 2 + X + 1) + 12x ^ 2

（x^2-6x+1）(x^2+x+1)+12x^2=(x^2+1)^2-5x(x^2+1)-6x^2+12x^2
=(x^2+1)^2-5x(x^2+1)+6x^2=(x^2+1-2x)(x^2+1-3x)=(x-1)^2(x^2-3x+1)
(x^2-6x+1)(x^2+x+1)+12x^2=(x^2+1)^2-5x(x^2+1)-6x^2+12x^2=(x^2+1)^2-5x(x^2+1)+6x^2=(x^2+1-2x)(x^2+1-3x)=(x-1)^2)(x^2+1-3x)
The final result is (x-1) ^ 2 + (x ^ 2-3x + 1)
The method is to expand all the formulas and then decompose them
You can do it yourself. The result may not be correct
Formula method of 2x ^ 2-5x + 1 = 0
a=2,b=-5,c=1
So △ = B & # 178; - 4ac = 17
So x = (5 - √ 17) / 4, x = (5 + √ 17) / 4
According to the formula x = (B ± √ (B & # 178; - 4ac)) / 2A
x=(5±√25-8)/4=(5±√17)/4
According to the formula: x = (B ± √ (B & # 178; - 4ac)) / 2A
x=(5±√25-8)/4
=(5±√17)/4
x*2-5/2x+1/2=0,x*2-5/2x+(5/4)*2-(5/4)*2+1/2=0;(x-5/2)*2=17/16;x=5/2+_ Root 17 / 4
If the value of 5Y of the fraction 3x-2y is 7, then the value of this fraction will be increased by 4 times
Seven
（3x-2y）/5y
x. Y is 4 times larger
It's four times up and down
The value of the fraction does not change
Seven
unchanged
Factorization-3x ^ 2 + 6x-18
-3x^ 2+6x-18
=-3(x^2-2x+6)
The above formula is equal to - 2x ^ 2 + 4x-2 + x ^ 2 + 2x-1-15
=-2（X^2-2X+1)-(X^2-2X+1)-15
=[(X^2-2X+1)+3][-2(X^2-2X+1)-5]
=(X^2-2X+4)(-2X^2+4X-7)
I don't know. Is this OK?
Solve the equations 4x + 7Y = 10,6x-11y + 28 = 0
4x+7y=10 (1)
6x-11y+28=0 (2)
(1)*11+(2)*7
44x+77y+42x-77y+196=110
86x=-86
X=1
Substituting (1)
-4*1+7y=10
Y=2
Factorization; 1 / 2x ^ 2 + XY + 1 / 2Y ^ 2
1/2x^2+xy+1/2y^2
=1/2(x^2+2xy+y^2)
=1/2(x+y)^2
The common factor of polynomial X & # 178; - 9 and X & # 178; + 6x + 9 is
x²-9=(x+3)(x-3)
x²+6x+9=(x+3)²
So the common factor is x + 3
The common factor of polynomials X & # 178; - 9 and X & # 178; + 6x + 9 is (x + 3)
x²-9=（x+3）（x-3）
x²+6x+9=（x+3）²
So their common factor is x + 3
X+3
(x + 3) (x-3) = x ^ 2-9, (x + 3) ^ 2 = X6 ^ 2 + 6x + 9, so the common factor is (x + 3)
3 √ 5x + 6 √ 3 = √ 5x √ 6x + 2 √ 2 ＜ 0
3√5x+6√3=√5x
2√5X=-6√3
X = - 6 √ 3 / (2 √ 5) = - 3 √ 15 / 5 (the numerator and denominator are all multiplied by √ 5)
√6x+2√2＜0
√6X
Who knows
1. 2√5x=-6√3
x=-6√3/2√5=-3√15/5
2. √6x＜-2√2
x＜-2√2/√6
x＜-2√3/3
Factorization: (1) quadratic XY of 3=______ （2）3（x-2）-2x（2-x）=_______ （3）（1-a）²-a（a-1）=______
2 times of X (a + b) - A-B (2) (m-n) & 178; - (n-m) (M + 2n) (3) x (a-b) 2n times + 2N-1 of Y (B-A)
(1) 2-xy = 9-xy of 3
（2）3（x-2）-2x（2-x）=（x-2）（3+2x）
（3）（1-a）²-a（a-1）=（1-a）（1-a+a）=1-a
X & # 178; - 9x-22. Factorization
Multiplication by cross phase
-9=-11+2
-22=-11×2
So:
x²-9x-22
=(x-11)(x+2)
I hope I can help you~
（x+2）（x-11）
(X-11) (x + 2) cross multiplication, if you have any questions, please ask me again?