(- 4 / 3x square, y Square) (3 / 4x square + XY-2 / 5Y Square)

(- 4 / 3x square, y Square) (3 / 4x square + XY-2 / 5Y Square)

(- 4 / 3x square, y Square) (3 / 4x square + XY-2 / 5Y Square)
=-The fourth power of X is Y & # 178; - 4 / 3x & # 179; Y & # 179; + 8 / 15x & # 178; the fourth power of Y
Factorization 6x & # 178; + 7x + 24m & # 178; - 12m + 9
（3x＋2）（2x＋1）
（2m-3）²
Factorization
6x²＋7x＋2
=(3x+2)(2x+1)
4m²－12m＋9
=(2m-3)²
6x²＋7x＋2
=(3x+2)(2x+1)
4m²－12m＋9
= (2x-3)²
7-6x = 5x + 1.8 to solve the equation
5X+6X=7-1.8
11X=5.2
X=5.2÷11
X=26/55
7-6X=5X+1.8 7-1.8=5x+6x 5.2=11x x=26/55
7-6X=5X+1.8
-6x-5x=1.8-7
-11x=-5.2
x=26/55
11x = 5.2 x = 26 / 55, hope to adopt, thank you~
52 / 11 en Wang adopted
When a is a value, the solutions of the equations 3x-5y = 2A, 2x + 7Y = A-18 are opposite to each other
Let x = - y, substitute 3x + 5x = 2A, get a = 4x; substitute the second formula, 2x-7x = 4x-18, get x = 2, then a = 8
X = - y
The original equations are changed to 3 (- y) - 5Y = 2A, 2 (- y) + 7Y = A-18
That is: - 8y = 2A, 5Y = A-18
So: a = 8
Solve the equations: 3x-5y = 16, 2x + 7Y = - 10
X=2，Y=-2
The factorization of 6 (X-Y) ^ 2 + 3 (Y-X) ^ 3 uses the method of quoting common factor
OK, it can be added
6(x-y)²+3(y-x)³
=6(x-y)²－3(x－y)³
=3(x-y)²[2－(x－y)]
=3(x-y)²(2－x＋y)
1.2-0.9 + 5x = 0.8, 7.2x-3.6x = 9x0.4
0.3＋5x＝0.8
5x＝0.5
x＝0.1
Given the constraint condition x-3y + 4 > = 0 x + 2y-1 > = 0 3x + y-80), the maximum value is only obtained at (2,2), and the value range of a is obtained
Why did I find your question? Despair
Factorization of common factor: 2x (x + y) & # (x + y) cubic
2X (x + y) & #178; - (x + y) cubic
=(x+y)^2(2x-x-y)
=(x-y)(x+y)^2
2x（x+y）²-（x+y）³
=(x + y) & # 178; [2x - (x + y)] [the common factor is (x + y) & # 178;]
=（x+y)²（2x-x-y)
=（x+y)²（x-y)
Our team will answer for you
The solution equation (1) 8x-16 = 0 (2) 2.4x + 1.2 × 2 = 7.2 (3) 12.5x-6x = 19.5
X=2
X=2
X=3
Let the variables X and y satisfy the constraint condition x ≥ x − y ≥ 02x − y − 2 ≤ 0, then the maximum value of Z = 3x-2y is 0______ .
When the answer is shown in the diagram, the maximum value of the objective function (z = 4.2) is drawn