How to calculate the tenth power of 1.06 is the calculator with DRG, 2ndf and other buttons

How to calculate the tenth power of 1.06 is the calculator with DRG, 2ndf and other buttons

First of all, it depends on whether your calculator is a scientific calculator with that kind of calculation function
If you have that function, you can see XY on the label beside the key
First input 1.06, press the key, then input 10, = to get the answer
X superscript y that:
1.06 - > x superscript Y - > 10 - > = 1.79084769654
I have a more complex formula for Android computing
How to use the four key mixed operation on the calculator
It depends on the model of the calculator
How does electronic calculator m + operate
M +, M -, Mr, MC are the storage keys of the calculator. M + key: when the calculation result or a certain value has appeared on the screen, press m + key, the calculator will save the number on the screen to the memory. At this time, the calculation is interrupted, and you can start to press the new number for new operation again. If you press m + key again, the current number on the screen will be
A problem of the first degree equation of one variable in elementary school
If the solution of the equation (2x 2-y) is one third of (x 2-y) - 1
The solution of 2 - (N-X) / 3 = 2x is x = 1
2-（n-1）/3=2
6-（n-1）=6
n-1=0
N=1
The latter equation should be n, right? Or the former n should be m,
Let n = 1 follow
y-3-2=2y-5
y-5=2y-5
-5+5=2y-y
Y=0
There is a problem with the title: N in the known condition, and m in the equation about y.
Factorization of x ^ 6-y ^ 6-2x ^ 3 + 1
Except for x ^ 6-y ^ 6-2x ^ 3 + 1
=(x^6-2x^3+1)-y^6
=(x^3-1)^2-(y^3)^2
=(x ^ 3 + y ^ 3-1) (x ^ 3-y ^ 3-1) is there any other way
After verification, there is no other way to solve this problem. Except the highest order item 6, there are only the cubic item and constant item of X, and there are no other secondary items of Y. we can only merge x ^ 6-y ^ 6-2x ^ 3 + 1 = (x ^ 6-2x ^ 3 + 1) - y ^ 6 = (x ^ 3-1) ^ 2 - (y ^ 3) ^ 2 = (x ^ 3 + y ^ 3-1) (x ^ 3-y ^ 3-1) through the secondary item of X
Given the function f (x) = 2XX + 1, X ∈ [- 3, - 2], find the maximum and minimum of F (x)
Because the function f (x) = 2XX + 1 = 2-2x + 1 & nbsp; is an increasing function in the domain [- 3, - 2], when x = - 3, the minimum value of the function is 3, and when x = - 2, the maximum value of the function is 4
Given that vectors a and B are not collinear, real numbers x and y satisfy the vector equation 3xa + (10-y) B = 2xb + (4Y + 4) a, then x =_____ ,y＝_____ .
3x=4y+4;
10-y=2x;
y=2;x=4;
How can't we use the multiple directions in the scientific calculator? It's just that the symbol doesn't respond
First, press the base number, then the symbol, then the index, and finally the = sign. Either the mode is wrong, I forgot to select the scientific calculation mode, or it's really bad~~
PDM
Sixty-eight
PDM
Sixty-eight
Sales problem of linear equation with one variable in elementary school
A store sells two pieces of clothes at the price of 120 yuan each at a certain time. One of them makes a profit of 50% and the other loses 25%. What's the total profit and loss of selling these two pieces of clothes?
The purchase price of a commodity is 1000 yuan, and the price is 1500 yuan. The store requires a discount of no less than 5% of the purchase price?
Suppose the cost of profitable clothes is x yuan, then the profit is 120-x yuan; if the known profit is 50%, then the profit is (x * 50%) yuan, 120-x = x * 50%, 120-x = 0.5x, 120 = x + 0.5x, 1.5x = 120, x = 80, then the profit of this clothes is 120-x = 40 yuan; suppose the cost of loss clothes is y yuan
Factorization: (X-Y + Z) ^ 2 - (2x-3y + 4Z) ^ 2
My answer is the same as you, but the teacher is wrong!
(x-y+z)^2 - (2x-3y+4z)^2
=[(x-y+z) +(2x-3y+4z)][(x-y+z) - (2x-3y+4z)]
=(3x-4y+5z)(-x+2y-3z)
-(3*x-4*y+5*z)*(x-2*y+3*z)
[(x-y+z)+(2x-3y+4z)]*[(x-y+z)-(2x-3y+4z)]
=(3x-4y+5z)*(-x+2y-3z)
Suggest to ask the teacher, the teacher may think you write nonstandard or have other reasons
(x-y+z)^2 - (2x-3y+4z)^2
=[(x-y+z) +(2x-3y+4z)][(x-y+z) - (2x-3y+4z)]
=(3x-4y+5z)(-x+2y-3z)