Given the position of rational numbers a and B on the number axis as shown in the figure (the absolute value of a is greater than B), then | A-B | is equal to A.A + B B. - (a + b) c.a-b d.b-a a0,———⊥——————————⊥—⊥————————→ a 0 b

Given the position of rational numbers a and B on the number axis as shown in the figure (the absolute value of a is greater than B), then | A-B | is equal to A.A + B B. - (a + b) c.a-b d.b-a a0,———⊥——————————⊥—⊥————————→ a 0 b

D. Nice picture
|A-B | equals b-a
|A-B | = A-B or B-A
Take the value greater than 0
What's the picture?
Choose D
|a-b|=-a+b
As shown in the figure, the rational numbers corresponding to a and B on the number axis are all integers. If the rational numbers a and B corresponding to a and B satisfy b-2a = 5, then please point out the position of the origin on the number axis
According to the number axis: B-A = 4, the simultaneous: B − 2A = 5B − a = 4, the solution: a = − 1b = 3, a represents - 1, B represents 3, then the origin is the point on the right side of a, as shown in the figure:
If the positions of rational numbers a, B and C on the number axis are shown in the figure, where 0 is the origin, | B | = | C |
1) Connect a, B, - A, - B with "<"
(2) What is the value of B + C?
(3) Judge the sign of a + B and a + C
So
Pro, pro, problem? Number axis?
Do you have the three questions
Questions?
If the positions of rational numbers a, B and C on the number axis are shown in the figure below, where 0 is the origin. (2) simplification: | C + a | + | B-C | - | b-a|
--a---------------b----0---------c------------>
According to the meaning of the title, | a | > | C | > | B |, so a + C
The function FX = (AX + b) / 1 + x ^ 2 is an odd function defined on (- 1,1), and f (1 / 2) = 2 / 5 is used to solve the inequality f (t-1) + (T)
So the definition of  / (x) = (178; + 1) = (x / 1); / (f) = (1); / (1); / (1); / (1); / (1); / (1); / (1); / (1); / (1); / (1); / (1); / (1); / (1); / (1); / (1); / (1); / (1); / (1); / (1); / (1); / (1); / (1); / (1); / (1); / (1); / (1) = (1); / (1); / (1); / (1); / (1); / (1) / (1) = (1) = (1; / (1); / (1); / (1); / (1) = (1; / (1); / (
The sum of {n ^ 2n} {n + 2n} sequence
The general term formula of {BN}
How to find an with Sn?
First question, the former minus the latter (simple)
an=4n,bn=1/2^(n-1)
So CN = (4N) ^ 2 * 1 / 2 ^ (n-1)
Because cn is greater than 0, so
c(n+1)/cn=(n+1)^2/2n^2
^ 2n (2) - 1
In △ ABC, a = 5, B = 3, COSC is the root of equation 5x2-7x-6 = 0, then s △ ABC=______ .
The solution is: x = 2 or x = - 35, ∵ COSC is the root of equation 5x2-7x-6 = 0, and COSC ∈ [- 1,1], ∵ COSC = - 35, C is the inner angle of triangle, ∵ sinc = 1 − cos2c = 45, a = 5, B = 3, then s △ ABC = 12absinc = 6
If the solution of the inequality kx2 + KX + 1 > 0 of X is any real number, then the value range of K is
Obviously, when k = 0, the inequality holds
When k ≠ 0,
If kx2 + KX + 1 > 0 is to be constant, it has to open up first, that is, k > 0
Secondly, there is no intersection between the image of quadratic function and x-axis, that is, the discriminant △
The known function f (x) = (AX-1) / (x ^ 2-4), when a
(AX-1) / (x ^ 2-4) 1 / a with x > 2 or X
If Sn and TN represent the sum of the first n terms of the sequence {an} and {BN} respectively, for any positive integer n, an = - 2 (n + 1), tn-3sn = 4N, find the general term formula of {BN}
An is obviously an arithmetic sequence
So A1 = - 4
Sn=1/2 ·(-4-2n-2)n=-n(n+3)
Then TN = - 3N (n + 3) + 4N = - 3N ^ 2-5n
T(n-1)=-3(n-1)^2-5(n-1)
The results show that BN = - 6n-2