On the number axis, the point representing the negative number is at () of the origin, the point representing the positive number is at () of the origin, and the number represented by the origin is () On the number axis, the distance from point a of 205 to the origin is (), the distance from point B of - 2.5 to the origin is (), and the distance between two points is () From the above question, we can guess that there are () points on the number axis with a distance of 4.5 from the origin, and the points that meet the conditions represent () A point starts from the origin of the number axis, first moves 2 units of length to the left, and then moves 3 units of length to the right. The number represented by the point is () Judgment: each store on the number axis represents a rational number The distance from the number axis to the origin is equal to 2 points of unit length, which means the number is 2 Given that there is a line segment of 100 unit length on the number axis, how many points representing integers may be covered by the changed line segment? The 205 of the first question is 2

On the number axis, the point representing the negative number is at () of the origin, the point representing the positive number is at () of the origin, and the number represented by the origin is () On the number axis, the distance from point a of 205 to the origin is (), the distance from point B of - 2.5 to the origin is (), and the distance between two points is () From the above question, we can guess that there are () points on the number axis with a distance of 4.5 from the origin, and the points that meet the conditions represent () A point starts from the origin of the number axis, first moves 2 units of length to the left, and then moves 3 units of length to the right. The number represented by the point is () Judgment: each store on the number axis represents a rational number The distance from the number axis to the origin is equal to 2 points of unit length, which means the number is 2 Given that there is a line segment of 100 unit length on the number axis, how many points representing integers may be covered by the changed line segment? The 205 of the first question is 2

On the number axis, the point representing the negative number is on the left side of the origin, the point representing the positive number is on the right side of the origin, and the number represented by the origin is (0). On the number axis, the distance between the point a representing 205 and the origin is (205), the distance between the point B representing - 2.5 and the origin is (2.5), and the distance between the two points AB is (207.5)
twenty point five
Two point five
Twenty-three
One
incorrect
incorrect
One hundred and one
On the number axis, the number from the origin to the right is --- A. negative number B. positive number C. non negative number D. non positive number
Select b, positive number does not include zero (zero is not a positive number)
As shown in the figure, the rational numbers corresponding to a and B on the number axis are all integers. If the rational numbers a and B corresponding to a and B satisfy b-2a = 5, then please point out the position of the origin on the number axis
According to the number axis: B-A = 4, the simultaneous: B − 2A = 5B − a = 4, the solution: a = − 1b = 3, a represents - 1, B represents 3, then the origin is the point on the right side of a, as shown in the figure:
Given that the coordinates of point a in triangle ABC are (1,2), the midline equations on AB and AC sides are 5x-3y-3 = 0, 7x-3y-5 = 0, the equation of BC is solved
It is suggested that C (a, b), C (a, b), C (a, b), C (a, b), C (a, b), C (a, b), C (a, b), C (a, b), C (a, B), C (a,
From C on the central line 5x-3y-3 = 0, 5a-3b-3 = 0,
From AC midpoint ((a + 1) / 2, (B + 2) / 2)
On the midline 7x-3y = 0, 7a-3b + 1 = 0,
So a = - 2, B = - 13 / 3,
C (- 2, - 13 / 3),
In the same way, we can find the B coordinate and then the equation of BC
Set a = {x | - 1 ≤ x ≤ 2}, set B = {x | x ≤ a}, if a ∩ B = & # 8709;, then the value range of real number a is?
Let s = {y | y = 3 x power, X ∈ r}, t = {y | y = x & # 178; - 1, X ∈ r}, s ∩ t be
The value range of real number a is a = {x | x ＜ - 1}
2,S∩T={y|y=3^x,y=x²-1,x∈R}
a>2;
S ∩ t = the intersection of x ^ 3 and x ^ 2-1
Given that the function f (x) = the square of X / ax + B is odd, f (1)
Given that the function f (x) = the square of X / ax + B is odd, f (1)
Given the first n terms of sequence {an} and Sn = n ^ 2 + N, let BN = 1 / Anan + 1, find the first n terms and TN of sequence {BN}
So: an = 2n BN = (1 / 4) · 1 / N (n + 1) 4bn = 1 / N (n + 1) = 1 / n-1 / (n + 1), so: 4tn = [(1-1 / 2) + (1 / 2-1 / 3) + ·· + (1 / n-1 / (n + 1))] = 1-1 / (n + 1) = n / (n + 1)]
In the triangle ABC, a plus B equals ten, a times b equals 12, and COSC is the square of the equation 2x minus 5x plus 2 equals 0 to a root
The side length C is 8. According to the cosine theorem, the square of C = a + B + 2Ab times COSC
If a = {x | x2-2x-3 ≤ 0}, B = {x | x ＞ a}, and a ∩ B = φ, then the value range of real number a is______ .
The set a = {x | x2-2x-3 ≤ 0} is reduced to a = [- 1, 3], while B = {x | x ＞ a} = (a, + ∞), ∩ B = φ, so a ≥ 3, so the answer is [3, + ∞)
The function f (x) = x square - 2x + 2, X belongs to [0,4], for any x belongs to [0,4], the inequality f (x) is greater than or equal to AX + a,
Find the value range of a
f(x)=x²-2x+2
f(x)>ax+a
X & # 178; - 2x + 2 ﹥ ax + a can be reduced to;
a(x+1)
Draw the function image directly, find a tangent line passing through negative one in {0,4}, and calculate the slope of the tangent line. As long as it passes through the line of negative one, the slope range of all the lines below the tangent line is the range of A