The parameter of electric energy meter is 220V 10 (20) A. when calculating the maximum power of electric energy meter, should 10A or 20A be used?

The parameter of electric energy meter is 220V 10 (20) A. when calculating the maximum power of electric energy meter, should 10A or 20A be used?

The designed maximum power is 241 * a
Xiaoming's electric energy meter is marked with 220V, 10a (20a). His family has 700W electric rice cooker, 150W TV set, 2000W electric kettle and 1500W electric bath
Q: can Xiao Ming use an electric shower when his family is watching TV (other appliances are not used)?
Yes, the current of the meter is 10a, and the power it can provide is 220 * 10 = 2200W, the TV is 150W, and the electric bath is 1500W
150+1500
If the electric energy meter is marked with 220 V 10A (20 A) 50 Hz, the total power of the electric appliance can not exceed how much w? 2200 w? 4400 w?
This statement is not unified. The teaching reference is based on 20a, but that is the maximum power in a short time
When we do the problem, it is calculated based on 10A. It is the maximum power that can ensure the normal operation of the circuit, so the total power is not more than 2200W
If the meter is marked with "220V & nbsp; 10A (20a)", the allowable rated power in the home circuit can reach______ In a short time, the electric power can reach______ .
According to the meaning of the parameters of the electric energy meter, if the output voltage of the electric energy meter is 220 V and the current in normal operation is 10 A, then the rated power of the home circuit is p = UI = 220 V × 10 a = 2200 W; if the maximum current allowed in a short time is im = 20 A, then the maximum electric power in a short time is PM = UIM = 220 V × 20 a = 4400 W
Know Tan ^ 2 @ = 2tan ^ 2 & + 1 and find the value of Cos2 @ + sin ^ 2 +?
Tan & sup2; a = 2tan & sup2; B + 1, then Tan & sup2; a + 1 = 2 (Tan & sup2; B + 1) so sec & sup2; a = 2sec & sup2; B, namely 2cos & sup2; a = cos & sup2; B, namely 1-2cos & sup2; a = 1-cos & sup2; bcos2a + Sin & sup2; b = 0
Set M = {y | y = x * x-4x + 3, X belongs to Z}, n = {y | y = - x * x-2x, X belongs to Z}, find m intersection n
M = {y | y = x * x-4x + 3, X belongs to Z} and N = {y | y = - x * x-2x, X belongs to Z}
You can write:
Y = x * x-4x + 3 x belongs to Z and y = - x * x-2x x belongs to Z
So finding m intersection n is to find the solution of y = x * x-4x + 3 and y = - x * x-2x x belonging to Z
y=x*x-4x+3
(x belongs to Z)
y=-x*x-2x
Namely: X * x-4x + 3 = - x * x-2x
Solution: no solution
So m intersection n is an empty set
Hehe, is that ok?
.
M ∩ n is a set of integer solutions of X * x-4x + 3 = - x * x-2x.
After finishing, we get 2x * x-2x + 3 = 0
Discriminant
When x is greater than 1, the square root of the square of (1-x) is reduced
x>1,(1-x)
The original formula is X-1
It is known that the number sequence {an}, the first term is 81, the number sequence {BN} = log3an, and the sum of the first n terms is SN. It is proved that {BN} is an arithmetic number
Proof: let {an} common ratio be q, for {BN}, logarithm is meaningful, when Q > 0An = A1 × Q ^ (n-1) n = 1, B1 = log3 (A1) = log3 (81) = 4N ≥ 2, BN = log3 (an) = log3 (A1 × Q ^ (n-1)) = log3 (A1) + log3 (Q ^ (n-1)) = log3 (81) + (n-1) log3 (q) = (n-1) log3 (q) + 4B (n-1) = L
If Tan (α + β) = 2tan α, we prove that 3sin β = sin (2 α + β)
∵tan(α+β)=2tanα,
∴sin(α+β)/cos(α+β)=2sin(α)/cos(α)
∴sin(α+β)*cos(α)=2cos(α+β)*sin(α)
∴2sin(α+β)*cos(α)=4cos(α+β)*sin(α)
∴3sin(α+β)*cos(α)-3cos(α+β)*sin(α)=sin(α+β)*cos(α)+cos(α+β)*sin(α)
∴3sin[(α+β)-α]=sin(α+β)*cos(α)+cos(α+β)*sin(α)
∴3sin(β)=sin[(α+β)+α]
That is: 3sin β = sin (2 α + β)
M = {x x & # 178; + X-6 ＜ 0}. N = {x x x & # 178; + 4x + a ＜ 0}. If n is included in M, find the value range of real number a
∵M=﹛x -2＜x＜3﹜
And N is contained in M
If n is an empty set
Discriminant = 16-4a < 0
A > 4
If n is not an empty set
x1=-2+√4-a,x2=-2-√4-a
Because x1 ＜ 3, X2 ＞ - 2, x1 ＞ x2
There is no solution
So a > 4