What is the specification of 2 * 2.5 square wire?

What is the specification of 2 * 2.5 square wire?

2 * 2.5 refers to two 2.5mm2 wires. The specific wire depends on the model marked in front of 2 * 2.5, such as vv2.2.5 (PVC sheathed power cable), rvv2 * 2.5 (plastic flexible cable), kvv2 * 2.5 (control cable), YC2 * 2.5 rubber sheathed cable, bvvb2.2.5 (copper sheathed cable)
When a bulb is connected to a circuit with a voltage of 220 V, the current passing through the bulb is 0.5 A, and the power on time is 1 h. how much electric energy does it consume and how much power does it consume?
How many kilowatts is it? I'm sorry, I typed it wrong
Power consumption: w = uit = 220V * 0.5A * 3600s = 3.96 * 10 ^ 5J
W = 3.96 * 10 ^ 5 / (1000 * 3600) = 0.11
P=UI=220V*0.5A=110W=0.11KW
W = Pt = 0.11kw * 10h = 1.1kwh = 1.1 degree
That's 1.1 degrees.
The power consumption is 1.1kwh, equivalent to 1.1 kwh.
w=uIt=220*0.5*3600s=396000J
One kilowatt hour is the common name of ten million hours, that is, the unit is kW. H
1 degree = 1kW. H = 360000j
So 396000j = 1.1 degrees
Power: P = UI = 220x0.5 = 110W = 0.11kw
Electric energy: w = Pt, t = 1H
w=0.11x1=0.11kw.h
11 degrees
0.11kw.h=0.11x3600000=396000J
Electric power P = UI = 220V * 0.5A = 110W = 0.11kw
Power consumption w = Pt = 0.11kw * 1H = 0.11kw * H = 0.11 degree
W = uit = 220 * 0.5 * 3600 = 3.96 * 10 ^ 5jw = uit = (220 * 0.5) / 1000 * 1 = 0.11 degree, which consumes 3.96 * 10 ^ 5J of electric energy and 0.11 degree of electric energy
Two copper wires of the same length and different thickness are connected in series in the circuit, I thick = I thin; u thick < u thin why
For the resistance of the same material, r = resistivity * L / s, where l is the length of the resistance and S is the cross-sectional area. According to the formula, the thin resistance is large, and in the same circuit, u = I * r, so the thin voltage is large!
Because the current of series circuit is equal everywhere, I coarse = I fine;
Because the resistance is smaller than u, the thinner the conductor is, the larger the resistance is.
The resistance is small when the cross-sectional area is large.
Wire 4 square 6 square what do you mean
Wire 4 square 6 square. Indicates that the cross-sectional area of wire conductor is 4 square mm and 6 square mm
The rated voltage of a light bulb is 220 V, the normal luminous current is 0.2 a, and it is powered for 5 min, then how much power is it, how much electric energy is consumed, and how much kW / h is it
[there should be a calculation process qvq
Power 44w
Energy 13200j
0037h / h
Two uniform copper wires with the same length and the ratio of cross-sectional area S1: S2 = 2:3 are connected to the circuit as shown in the figure, then the ratio of resistance R1: R2 of the two wires is equal=______ The ratio of the electric field force on the free electron moving directionally in two wires is F1: F2=______ .
The length and material are the same, and the ratio of cross-sectional area is S1: S2 = 2:3. According to r = ρ ls, the ratio of resistance r1r2 = 32 is in series circuit, and the current is equal. If I is set, the electric field force F = EQ = udq = ille exerted by the free electron when it moves directionally in two wires. Therefore, the ratio of electric field force F1: F2 = R1: R2 = 3:2 exerted by the electron when it moves directionally in two wires, so the answer is: 3:2; 3:2
What is the area and unit of the cable
I'm a coal mine electrician. When I work, I always talk about 6 square meters of cable, 30 square meters of cable, etc. (three-phase four wire), so what's the unit of square meters here? 6 ah 30 ah refers to the cross-sectional area of the cable () including the outer rubber layer, or the cross-sectional area of the copper core inside the cable (copper area)?
I hope you can answer
For example, for a 70 square meter cable (three-phase four wire, ground wire thinner), does that mean that the cross-sectional area of the copper core of the four wires is added up? I have measured it with a vernier caliper. According to the calculation of square millimeter, the data is quite different from 70. It's not that I don't know. It's that the actual area is too different from the theoretical area that I doubt
Square the cross-sectional area of a single conductor, in square millimeter. As for the difference between the area you measured and the theoretical area, this is very normal. Almost all cable factories will cut corners, reduce the core diameter, and save costs. If the difference is too much, you can send it to the Bureau of technical supervision
A light bulb is connected to a voltage of 220 V, and the current passing through the bulb is 0.5 A. how much electric energy does it consume? How many kilowatts of electricity does it consume in one hour?
A light bulb is connected to the voltage of 220 V, and the current passing through the bulb is 0.5 A. how much power does it consume in one hour of power on event? How much to drink
Electric energy w = Pt
P = u * I = 220 V * 0.5 = 110 w
One kilowatt hour, so the electric power = 110W / 1000 = 0.11kw/h
So w = 3.6 * 10 ^ 6 * 0.11W * 1H = 3.96 * 10 ^ 5J
So 396000 joules
0.11 kWh
How to calculate the short circuit current of two 2 square millimeter copper wires in the lighting circuit at 100 meters? Thank you
R=ρL/S
ρ is the resistivity of the material, in (Ω. M) ρ = 1.75 × 10-8
L is the length, unit (m), here is 100 * 2 = 200 (m)
S is the sectional area, in square meters (M2) s = 2 / 10-6
R=1.75×10-8×200×2/1000000=7Ω
The lighting voltage is 220 V, so I = u / r = 220 / 7
May I ask: BV and bvr1 - 240 square copper wire national standard single conductor diameter is how many
national standard:
BV 1-240 square conductor diameter and number!
Bvr1-240 square conductor diameter and number!
Nominal section core structure (mm 2) number / diameter (mm) 1.0 (a) 1 / 1.131.0 (b) 7 / 0.43 rated voltage 450 / 750V bv nominal section core structure (mm 2) number / diameter (mm) 1.5 (a) 1 / 1.381.5 (b) 7 / 0.522.5 (a) 1 / 1.782.5 (b) 7 / 0.684 (a) 1 / 2.254 (b) 7 / 0.856 (a