1. The actual power of a 220 V, 100 W light bulb is 2 when it is 110 v. two 220 V, 100 W light bulbs are connected in series in the circuit to calculate the power consumption after 1 min

1. The actual power of a 220 V, 100 W light bulb is 2 when it is 110 v. two 220 V, 100 W light bulbs are connected in series in the circuit to calculate the power consumption after 1 min

Resistance of bulb: r = u & # 178 / P = 220 & # 178 / 100 = 484 (Ω)
Actual power at 110V: P = u '² / r = 110 & #178 / 484 = 25 (W)
A: slightly
2. Two 220 V, 100 W bulbs are connected in series in the 220 V circuit to calculate the actual power and the electric energy consumed in 1 min?
Bulb resistance: R1 = R2 = u & # 178 / P = 220 & # 178 / 100 = 484 (Ω)
Two identical bulbs are connected in series in the 220 V circuit. According to the law of partial voltage, we can get: U1 = U2 = 110 (V)
P real 1 = P real 2 = U1 & # / r = 110 & # / 484 = 25 (W)
P total = 2p real 1 = 2 × 25 = 50 (W)
Wtotal = ptotal t = 50 × 60 = 3000 (J)
A: slightly
1. The actual power of the light bulb with 220 V and 100 W is 25 W at 110 v
2. Two 220V, 100W bulbs are connected in series in the circuit, and the power consumed after 1min is 25 * 2 * 60 = 3000j
(1) The bulb resistance R remains unchanged, so p = u ^ 2 / R is reduced to 1 / 4 of the actual power, i.e. P = 25W.
(2) After series connection, the two voltages are both 110V, so the total power consumption is 2 × 25 = 50W.
W = Pt = 3000J
The height of a trapezoid is 6.5cm, and the area is 52cm. Two trapezoids can be used to form a parallelogram with the height of 6.5cm and the bottom of () cm
The bottom is (16) cm
The bottom of the parallelogram is the sum of the top and bottom of the original trapezoid,
Therefore, the bottom is: 52 × 2 △ 6.5 = 16 cm
Bottom: 52 × 2 △ 6.5 = 16cm
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In the working principle circuit diagram of electric rice cooker (series circuit), are the two resistors in the state of heat preservation or heating?
The electric cooker controls two parallel resistances through the switch. They all work for heating. When the low resistance (tens of Ohm) is disconnected, it doesn't work, and the high resistance work for heat preservation
How many hours can a "220 V 100 W" bulb work normally with 1 degree of power?
Ten hours
1 kwh = 1000WH
1000Wh/100W=10h
A: 1 kilowatt hour can make 100W bulb work normally for 10h
10 hours question: process?
When the height of a group of opposite sides of a parallelogram is 6cm, its bottom is 7.5cm, and the length of the other group of opposite sides is 9cm. What's the corresponding height?
Equal utilization area
6 × 7.5 = 45 square centimeter
5 cm
Standard for insulation resistance of cables
How to solve the problem that there is no relative ground resistance of 0.5m * 120 after one year's use
Insulation resistance of wire core to sheath: 3KV should not be less than 50m Ω, 6kV and above should not be less than 100m Ω. There is no clear standard for old cable, which is mainly affected by its environmental temperature and humidity and other factors. Therefore, the insulation resistance values are different at different times
A bulb is marked with 220V 100W. What is the current passing through the bulb during normal operation?
Junior high school questions, according to P = UI
I=P/U=100÷220=0.44A
High school problems are not enough;
The solution of the problem is as follows
According to P = UI cos & # 216
I = P △ (UCOS & # 216;) cos & # 216; is the power factor, generally between 0.8 and 0.95
100W/220V=0.4545A
If it's a junior high school question, then the answer is about 0.45a. If it's a senior high school question, the conditions are not enough. If it's a college question, I'm sorry, I won't either
With Ohm's theorem, I current = P watt / u voltage can be solved
0.45A
P = UI, so I = P / u = 100 / 220 = 0.45a
I've read it. The answers from upstairs are reasonable.
If the length and width of a rectangle are √ 10cm and 2 √ 5cm respectively, the area of the rectangle is CM & # 178;
√10cm*2√5cm=10√2cm²
√10*2√5=10√2cm²
How to measure cable insulation resistance with megohmmeter?
Where are the two levels of megohmmeter connected? Whose insulation test is required by the standard? Is it the cable sheath? Or the insulation between two core wires?
Low voltage 380V / 220V cable, please introduce which point to connect when testing? What part of insulation resistance to measure? Normal range to measure
Don't copy from Internet, please answer my question above, the test position of high and low voltage cable is different
Connect to the two strands of wires you want to test, and the insulation resistance between the two wires is measured. You need to measure the wire core. If you get stuck on the wire skin, it is not measured. There are many things to be tested, such as phase to phase test, phase to zero test, phase to ground test and zero to ground test. You can refer to the table of insulation resistance test record, and the above test contents are all included. The test value shall not be less than 0.5 megohm
How many hours can a "220 V 100 W" bulb work normally
To calculate the formula and process
It can work for 10 hours for the 220v100w bulb, because the single-phase line takes 1000W / h as 1 kilowatt hour (1000W, its current is 4.5a)