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How much copper does a meter of 3 * 120 cable contain?
3×120=360/1000000=0.00036M³×8.9≈0.0032×1000=3.2KG
Please tell me the specific model.
A bulb is connected to a circuit with a voltage of 220 V, the current passing through the bulb is 0.5 A, and the power on time is 1 h. how much electric energy does it consume? (required process)
Just use the formula
P＝UIt
u＝220
i＝0.5
T = 3600 seconds
P = 396000 joules can be obtained
When the voltage at both ends of a conductor is 3V, the current passing through it is 0.5A, and the resistance of the conductor is () if the voltage at both ends of the conductor increases
R = u / I = 3V / 0.5A = 6ohm
So: the resistance of the conductor is (6 Ohm)
If the voltage at both ends of a conductor increases to a certain value, what is the resistance of the conductor?
The resistance is still 6 ohm, because the resistance is related to its material, length and thickness, and has nothing to do with the voltage
How many catties of copper are there in 350 square meters and 240 square meters of cable?
350 square mm: 3.50 × 100 × 8.9 = 3.115kg/m
240 square mm: 2.40 × 100 × 8.9 = 2.136 kg / M
M = the volume of copper multiplied by the density of copper.
How much is the actual power of the two lamps if the 220v60w lamp and the 220v15w lamp are connected in series on the circuit with the power supply of 220V
Resistance of 60W = 220 * 220 / 60
15W resistance = 220 * 220 / 15
Total power = 220 * 220 / (220 * 220 / 60 + 220 * 220 / 15) = 12W
60W bulb resistance = 220 * 220 / 60 = 8050
15W bulb resistance = 220 * 220 / 15=
When connected in series, the current is 220 / [220 * 220 / 60 + 220 * 220 / 15]
Then the actual power of 60 bulb is 220 / [220 * 220 / 60 + 220 * 220 / 15] times 220 / [220 * 220 / 60 + 220 * 220 / 15] times 220 * 220 / 60
The actual power of 15 watt bulb is 220 / [220 * 220 / 60
60W bulb resistance = 220 * 220 / 60 = 8050
15W bulb resistance = 220 * 220 / 15=
When connected in series, the current is 220 / [220 * 220 / 60 + 220 * 220 / 15]
Then the actual power of 60 bulb is 220 / [220 * 220 / 60 + 220 * 220 / 15] times 220 / [220 * 220 / 60 + 220 * 220 / 15] times 220 * 220 / 60
The actual power of 15 watt bulb is 220 / [220 * 220 / 60 + 220 * 220 / 15] times 220 / [220 * 220 / 60 + 220 * 220 / 15] times 220 * 220 / 15
If it's an incandescent lamp, calculate the resistance and add it up for power consumption.
R:806+3226=4032
P=U*U/r=12W
The other lights are of different construction.
The total power equals 75 WATTS.
After 60W and 15W are connected in series, the power is 220 * 220 (220 * 220 / 60 + 220 * 220 / 15) = 12W
But this solution has no practical use, because after the 60 watt and 15 Watt lamps are connected in series, the partial voltage is 44 V and 176 V respectively. The 15 watt bulb has some red light, and the 60 watt lamp will not light up.
When the voltage at both ends of a conductor is 3V, the current in the conductor is 0.5A. If the voltage increases to 6V, the current in the conductor is 0.5A____ ,
When the voltage at both ends of a conductor is 3V, the current in the conductor is 0.5A, if the voltage increases to 6V
What is the current in the conductor____ If the voltage is reduced to 1.5V, the current in the conductor is____ If the voltage is 0V, the current in the conductor is____ The resistance in the conductor is_____
1A,
0.25A
0A
6 Euro
1A 0.25A 0A 6Ω
3-phase 4-wire 120 square meter cable?
3 * 120 + 1 * 70 of armored copper core is 5.37kg/m
3 * 120 + 1 * 70 without armored copper core is 4.44kg/m
3 * 120 + 1 * 70 of armored aluminum core is 2.71kg/m
3 * 120 + 1 * 70 without armored aluminum core is 1.77kg/m,
These are approximate weights
How much heat can 30000 watts of electricity generate in one minute at 220 V?
The heat generated by 30000 watts per minute is:
30000 watts * 60 seconds = 1800000 joules
The unit converted to card is:
1800000 joules / (4.18 joules / card) = 430622 cards
Under the condition of this topic, there is no need to participate in the calculation
When the voltage at both ends of a conductor is 3V, the current passing through it is 0.5A, and the resistance of the conductor is calculated; when the voltage at both ends of the conductor is 6V, what is the current passing through it?
∵ I = ur, ∵ conductor resistance R = UI = 3v0.5a = 6 Ω; when u ′ = 6V, the current through the conductor I ′ = u ′, r = 6V 6 Ω = 1a. A: the conductor resistance is 6 Ω; when the voltage is 6V, the current through the conductor is 1A
How to calculate the over current of a square wire
According to the wire type, current flow, etc. to determine the wire length
Generally, 5-8a, considering the above conditions, the general calculation is conservative. Generally, 1kW per square meter
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