![](data:image/svg+xml;utf8,<svg xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" viewBox="0 0 72 71" width="72"></svg>)
Can two 2.5 wires be used together as a 6 square one? Is the current passing through the two wires the same? It's better to have theory, authoritative theory. I'm adding points
As soon as I see, I know that the building owner is studying electrical engineering. This question is very professional. I can't answer it well. I'll try to answer it. I'm not surprised if I'm wrong
In two cases, "whether two 2.5 square wires can be used as 6 square wires together" does not hold: first, it does not hold in DC circuit; second, it does not hold when 2.5 square wires are multi strand wires and 6 square wires are multi strand wires
It is true when it is used in AC circuit and 2.5 square line is single strand line and 6 square line is single strand line
The diameter of 6 square single strand is 2.764mm, and the section perimeter is 8.6832mm;
The diameter of 2.5 square single strand is 1.7841mm, and the section perimeter is 5.605mm
In AC circuit, the resistance of conductor is not only Ohm's law, but also the skin effect of conductor
The actual resistance is: RJ = s / P * radical (2 π Fu / ρ) * ρ * L / s
The s in the formula is eliminated, that is to say, the resistance has nothing to do with the cross section, but only with the perimeter of the cross section, and it is inversely proportional to the perimeter of the cross section
Then the section perimeter of two 2.5 square single strand wires is 2 * 5.605 = 11.21mm, which is larger than the section perimeter of a 6 square single strand wire of 8.6832mm, so the resistance of two 2.5 square single strand wires is less than that of a 6 square single strand wire, so the conclusion is valid
I hope I can help you
If 20 identical small bulbs are connected in series in the 220 V circuit, the voltage at both ends of each small bulb is 0___ If they are connected in a 110V circuit, the voltage at both ends of each small bulb is____ V
11 V and 220 V respectively
In the series circuit, if the resistance is the same, each load will share the power supply voltage equally, so the voltage of each bulb in the series circuit is 220 / 20 = 11V
Associated circuit, each load voltage is the same, so the voltage of each bulb in parallel is equal to the supply voltage of 110V
Series partial voltage, parallel shunt, so it is 11V 110V
For the different bulbs connected into the circuit, the bright ones are: those with large current, large voltage at both ends, large resistance and high electrical consumption
For different light bulbs connected in parallel, the brightness is greater: the current through the light bulb is greater; for different light bulbs connected in series, the resistance value and electrical consumption rate are greater if the voltage at both ends is greater
The bright current is the same. If the voltage at both ends is large, the resistance value is large, and the power consumption is also larger.
Assuming the same bulb and constant resistance, the current, voltage and power consumption are the maximum and brightest.
parallel connection? Or in series?
I now have two three core 150 square copper core cables. If I want to use one of the two cables as one phase, what will happen to the current carrying capacity
The current carrying capacity of 3 * 150 copper cable is 293A, and that of 3 * 300 copper cable is 454a. If two cables are used in parallel for more than 550A, it is estimated that there is no problem. If two 120 bare aluminum wires are used in high voltage lines, the current carrying capacity is absolutely greater than that of one 240 wire, and the cable should not be less than the sum of the two cables
When the voltage of W484 bulb is 220 V, the current of W484 bulb is 220 v
Current: I = P / u or I = u / R
Current: I unit a
Voltage: u
Power: P
Resistance: R
Current formula: 1A = 1000mA
I = u / r = 220V / 484 Ω = 0.45a = 450mA (MA)
The bulb is a pure resistive load.
Current: I = P / u or I = u / R
Your resistance doesn't match the power!
The resistance of a 200W bulb should be 242 ohm. 484 ohm is 100W.
Current = power / voltage = 200 / 220 = 0.909a
Does the greater the current, the greater the brightness of the bulb? Does voltage or resistance or actual power also affect the brightness of the bulb?
Please explain one by one
The greater the power, the greater the brightness~
When the voltage is low, the actual power is lower than the rated power, and the bulb is dark, otherwise it is on. However, all of these will cause harm to the bulb
The higher the current is, the higher the power is, the higher the brightness is, the higher the voltage is, the higher the power is, the higher the brightness is, the lower the resistance is, the higher the power is, the higher the brightness is
Well, it depends on who you are.
If you answer it as a simple question: Yes
If the brain swerves: the first one is uncertain, and the second one is positive.
If it is regarded as an academic issue, it needs to add some additional conditions to treat it differently. For example, the same voltage? Or the rated voltage and so on? ... unfold
Well, it depends on who you are.
If you answer it as a simple question: Yes
If the brain swerves: the first one is uncertain, and the second one is positive.
If it is regarded as an academic issue, it needs to add some additional conditions to treat it differently. For example, the same voltage? Or the rated voltage and so on? Put it away
How many square meters of wires does a 4 kW appliance need
The meter is about 100 meters away from my home, and it uses 4 square meters * 2 aluminum wires. Now my home's electrical appliances have 4 square meters of aluminum wires, which is a little dangerous or sheathed. The distance between the two wires is very close, and it's hard to say if they are overloaded and heated
The 100 W 220 V light bulb and 15 W 220 V light bulb are connected in series with 220 V power supply, and the current and voltage of each light bulb are calculated
The resistance of the first bulb R1 = u ^ 2 / P = 220 ^ 2 / 100 = 484 Ω
The resistance of the second bulb R2 = u ^ 2 / P = 220 ^ 2 / 15 = 3226.67 Ω
So the series current I = u / (R1 + R2) = 220 / (484 + 3266.67) = 0.06a
The voltage of the first bulb U1 = I * R1 = 29V
The voltage of the second bulb U2 = 220-29 = 191v
The working current of each bulb is I = 3 / 11a
100w220v lamp voltage 132v
15w220v bulb voltage 88v
What is the relationship between the voltage and the current when the resistance becomes larger (smaller)? What is the relationship between the current and the voltage becoming larger (smaller) and the brightness of the bulb?
Which light of pz220v25w and pz220v30w is on? (why?), how to mark the magnetic induction line? What kinds of communication methods are there? How to connect the relay?
When the voltage is constant, the greater the resistance, the smaller the current. When one side of the voltage or current is constant, the change of the other side is proportional to the change of the brightness of the bulb. When the voltage is the same, the lamp with high power is brighter. That is, 30W is brighter than 25W, which is inevitable
How many kilowatts can a square meter of wire and cable carry
1KW
RELATED INFORMATIONS
- 1. Know a thing power is 1500W, voltage is 220V, how to find its resistance? Fine formula!
- 2. When a resistor is applied with 1V voltage at both ends, the current passing through is 200mA, and its resistance value is______ Ω; if 2V voltage is applied at both ends of it, its resistance is______ Ω, the current passing through is______ A．
- 3. How much wire and switch should be used when the total power of 380V power equipment is 60kW?
- 4. The rated voltage is 220 V, the power is 40 W, and the resistance is calculated
- 5. The voltage at both ends of a conductor is 3V, the current passing through it is 0.3A, and its resistance is 10 Ω. When the current passing through the conductor is 0.5A, its resistance is Ω
- 6. What kind of wire should be used to install a 15kw motor Is it OK to use 6 square meters or more?
- 7. The size of a household electric iron is 220 V 800 W. it can generate J heat and use kwh electric energy after 10 minutes of normal operation
- 8. What is the resistivity of 700m copper wire? What is the resistivity of 700 meters copper wire? How much current can 10 square copper wire bear at most? What is the maximum current that a 700 meter copper wire can pass?
- 9. The rated power of refrigerator is 70W, the power consumption is 0.5kw.h/24h, and the rated power of TV is 65W
- 10. 10. - 16-25-35-50-70-95 square meters of cable wiring to use how much copper nose What is the size of copper nose for 10,16,25,35,50,70,95 square cable connection
- 11. Does the total voltage and current in parallel circuit change with the resistance
- 12. In the home circuit, the voltage must be 220 V, and the resistance of the electric stove is very large. According to P = u / R, the power should be very small, but why is the power of the electric stove very large? Moreover, the higher the resistance of other electrical appliances, the greater the power?
- 13. How much copper does a meter of 3 * 120 cable contain?
- 14. When the voltage at both ends of the conductor is 6V, the current passing through it is 0.6A, and the resistance is 10 ohm. If the voltage at both ends of the conductor is 3V, what is the current and resistance of the conductor
- 15. 1. A bulb connected to a 220 V circuit, the current through the bulb is 0.5 A, the power on time is 1 h, how much energy does it consume? How many kilowatt hours?
- 16. What is the specification of 2 * 2.5 square wire?
- 17. When the constant voltage U is applied to both ends of a metal wire with uniform thickness, the current intensity passing through the metal wire is I, and the average rate of directional movement of free electrons in the metal wire is v. if the metal wire is elongated to make its length twice the original length, throw it to both ends and apply the constant voltage u, then The rate of directional movement of free electrons is v / 2 I know that the current becomes a quarter. Why does the rate become a half?
- 18. 1. The actual power of a 220 V, 100 W light bulb is 2 when it is 110 v. two 220 V, 100 W light bulbs are connected in series in the circuit to calculate the power consumption after 1 min
- 19. The sliding resistor is connected to the circuit by changing the resistance______ To change______ &The size of the
- 20. A measuring cylinder is 1m high with a bottom area of 40DM and a vertical slender tube with a length of 1.2m and a cross-sectional area of 5cm A measuring cylinder is 1m high with a bottom area of 40DM and a vertical slender pipe with a length of 1.2m and a cross-sectional area of 5cm. When the cylinder and the long pipe are filled with water, what are the water pressures on the upper and lower bottom of the cylinder and the gravity of the water in the cylinder and the pipe? (g = 10N / kg)