When the coil resistance of a motor is 1 ohm, the voltage applied at both ends of the coil is 2V, and the current is 0.8A, the electric energy consumed by the motor in normal operation for one minute is____ J, What is the converted mechanical energy J

When the coil resistance of a motor is 1 ohm, the voltage applied at both ends of the coil is 2V, and the current is 0.8A, the electric energy consumed by the motor in normal operation for one minute is____ J, What is the converted mechanical energy J

Nine point six
The coil resistance of a motor is 0.4 ohm. When the voltage applied at both ends is 220 V, the current passing through it is 5 a
The coil resistance of a motor is 0.4 ohm. When the voltage applied at its two ends is 220 V, the current passing through it is 5 A. how much mechanical work does this motor do per minute?
The input power is p input = u * I = 220 * 5 = 1100 W
The heating power of coil resistance is p heat = I ^ 2 * r = 5 ^ 2 * 0.4 = 10 watts
The output power (mechanical power) is p output = P input-p thermal = 1100-10 = 1090w
The mechanical work is w = P * t = 1090 * 60 = 65400 joules
When an electrical appliance works normally for 5 hours, the electric energy expression changes from (2158) (2) to (2162) (2), which consumes electric energy_ The rated power is_ tile
When an electrical appliance works normally for 5 hours, the number of electric energy expression changes from (2158) (2) to (2162) (2). The electrical appliance consumes 4 degrees of electric energy and the rated power is 800 watts
2162.2-2158.2 = 4 degrees = 4kwh
p=W/t=4kWh/5h=0.8kw=800w
2162.2-2158.2 = 4 (degrees)
Power = 4x1000 / 5 = 800W
You don't understand
I guess that number should be the number of laps
Subtract the two numbers, multiply the energy per turn, and divide by five
2162.2-2158.2=4kw
p=w/t=4kw/5h=0.8kw=800w
How much work does the current do and how many kilowatts does the current consume in 10 minutes when an electric furnace with 80 ohm resistance is connected to a voltage of 220 V?
363000j. Consumed about 0.1 kwh
According to w = (u ^ 2 / R) * t
=220^2*600/80J=363000J
1 kwh = 3.6 * 10 ^ 6J
Therefore, 363000j = 363000 / 3.6 * 10 ^ 6 = 0.1 kwh
If the two lamps are connected in series in a 220 V circuit, then ()
A. Both lights are on normally
B. A light is on, B light is not on
C. Both lights don't work
D. It is darker than normal operation
In short, the light with small wattage is brighter, and the light with large wattage is darker
A lamp 100W / 110V = 0.91a, 110V / 0.91a = 121 ohm. B lamp 200W / 110V = 1.82A, 110V / 1.82A = 60 ohm
220 V / (121 + 60) = 1.2 A (the current of two lamps connected in series in 220 V) 1.2 A is more than 30% of that of a lamp 0.9 a, which is likely to burn out a lamp. Once a lamp burns out, both lamps will not work
A. Both lights are on normally
R = u ^ 2 / P, so r a > R B. Therefore, after series connection, the voltage of lamp a is greater than 110V, and that of lamp B is less than 110V. Both lights are not working properly. So light a is on and light B is off. To be exact, it's not bright.
After a period of time, a lamp will burn out quickly due to high voltage! If the circuit is open, both a and B will not light up.
The difference between copper core wire and aluminum core wire, the difference between 220 V and 380 V, what's the difference in calculation method? Beginners seek answers, hope friends help
How much current does a copper wire need for a large current?
In 380V voltage, how much current is allowed for a square of copper core wire? How much current does a kilowatt need? How much wire does a kilowatt need? What is the copper core wire like?
How is it calculated,
Compared with aluminum conductor, copper conductor has better thermal stability and higher rated current, that is to say, 10 square copper conductor is equivalent to 16 square aluminum conductor. Corrosion resistance, tensile strength and oxidation resistance are also better than aluminum conductor. In pure resistance circuit, power is the product of voltage and current
How long does it take for a 100 watt appliance to consume electricity? How do you calculate it?
The former is the energy value, and the latter is the power. As long as the former is divided by the latter, the latter can be equal to 10 hours
The electric furnace with a resistance of 90 ohm is connected to a 220 V power supply. When it is electrified for 3 minutes, how much work has the current done
W = P *t =( U*U / R ) * t = (220 * 220 / 90) * 3 * 60 = 96800 w
Connect the PZ 220 - 20 bulb to the 220 V and 110 V circuit respectively. What is the actual power consumption of the bulb?
The power of the lamp connected to 220 V circuit is 20 W. the power connected to 110 V circuit is 5 W
Tips: PZ 220 - 20 is to tell you that the rated voltage of the lamp is 220 V and the power is 20 W. obviously, when the lamp is connected to 220 V, its power is 20 W. then use the parameter PZ 220 - 20 to calculate the resistance of the lamp: r = u ^ 2 / P = 220 x220 / 20 = 2420 Ω
According to the power formula, P = u ^ 2 / r = 110 x 110 / 2420 = 5 W is the power when the bulb is connected to 110 v
The power in the 220 V circuit is 20 watts! Because at this time the normal light ah!
The resistance is r = u ^ 2 / P = 220 ^ 2 / 25 = 1936 ohm, and the current electric power is p = u ^ 2 / r = 110 ^ 2 / 1936 = 6.25w
classmate! Remember this conclusion (half the voltage, quarter the power)
Twenty
Five
In pure resistance, the lower the voltage, the higher the current, so 10% of 20
Each room is about 3000 watts. There are 32 rooms on the first floor, with a total length of about 60 meters. If you use 220 V, how many square meters of copper wires do you need? 380 V?
Only, I just modified the calculation of the first floor, because there are some problems in the calculation of the first floor. 3KW * 32 = 96000w = 96kw220v total power cable current: I = P / u = 96kw / 220V ≈ 436 (a) 380V total power cable current: I = P / u = 96kw / 380V / 11.732/0.85 (this number may not be 0.85, because I don't know your electrical equipment) ≈ 1