How to change the plural number of nouns ending with "O" in English words?

How to change the plural number of nouns ending with "O" in English words?

There is life, such as patotoes
Add s directly to the inanimate, such as pianos
The living, plus es, such as potato, tomato, heros, Negroes
Inanimate, just add s, such as photos,
General plus es, special have a few you want to check, like hero is plus s
When countable nouns become plural in English, the ending of F and Fe should be changed. Which word has a special ending?
The exam is coming soon! Please
Ending with the consonant ten y, change y to I plus es
A living addition ending in o
Ten seconds in general
Ten es ending with s x sh Ch
1. Add s directly, such as: belief --- beliefs roof --- roof;
safe---safes gulf---gulfs；
chief----chiefs cliff---cliffs
2. To F, Fe and ves, such as: half --- haves knife --- knives
1. Add s directly, such as: belief --- beliefs roof --- roof;
safe---safes gulf---gulfs；
chief----chiefs cliff---cliffs
2. Remove F, Fe and add ves, for example: half --- halves knife --- knives
leaf---leaves wolf---wolves
wife---wives life---lives
thief---thieves
3. Both can be added. Both can be added. For example: Handkerchief: Handkerchief / handkerchieves
Sorry, your answer didn't help me
What is the plural of a noun ending with th
How to read, how to change
The plural of the noun ending th plus s
Th pronounces the consonant [θ], the plural ends with [S],
Voiced consonant [ð], plural ending [Z]
It is in accordance with the principle of clearing away the turbid and Yuan being turbid
Hope it helps!
When she asked a math problem, Beibei thought of a number in her mind, so she added, subtracted and divided the number with herself, and the sum and difference quotient was 1
Beibei thought of a number in her mind, so she added, subtracted and divided the number with herself. The sum difference quotient was 10.6. The number in Beibei's mind was []
Beibei thought of a number in her heart, so she added it to herself, subtracted it, and divided it. The sum quotient was 10.6
0 + 1 = 110.6-1 = 9.69.6 divided by 2 = 4.8 is 4.8
Let a = {the square of X | x-8x + 15 = 0}, B = {x | AX-1 = 0}, if B is contained in a, find the set of real numbers a
Why is it that if B = an empty set, then a = 0, I know that an empty set is an equation with no solution
So the coefficient of X is 0
So, isn't a equal to any number OK
Yeah
So here we can have a = 0
In addition, a ≠ 0
Then x = 1 / A
Because a = {3,5}
So 1 / a = 3, 1 / a = 5
So it's {0,1 / 3,1 / 5}
If the maximum and minimum values of F (x) = x3-3x-a in the interval [0, 3] are m and N respectively, then the value of M-N is ()
A. 2B. 4C. 18D. 20
When 0 ≤ x ＜ 1, f ′ (x) ＜ 0; when 1 ≤ x ≤ 3, f ′ (x) ＞ 0. Then f (1) is the minimum, then n = f (1) and f (0) = - A, f (3) = 18-a, and F (3) ＞ f (0), the maximum is f (3), that is, M = f (3), so M-N = f (3
What is the sum of the sum, difference, product and quotient obtained by adding, subtracting, multiplying and dividing an integer with itself?
Every step should be explained in detail
The square of 2x + 121 = 0
Square of X + 2x-120 = 0
Release x = - 12, x = 10
Let this number be X
The order of addition, subtraction, multiplication and division is 2x, 0, x ^ 2, 1
2x+0+x^2+1=121
x=10
Let the number be a
a+a+(a-a)+a*a+a/a=121
2a+a*a=120
A = 10 or a = - 12
Let a = {x | x2-8x + 15 = 0}, B = {x | AX-1 = 0}, if B ⊆ a, find the value set of real number a
Set a = {x | x2-8x + 15 = 0} = {3,5}, by the meaning B ⊆ a, when a = 0, B = ∞, meet the requirements; when a ≠ 0, n = {1A}, ∧ 1A = 3 or 5, a = 13 or 15, so the set of real number a is: {0,13,15}
It is known that y = f (x) is an even function. When x > 0, f (x) = x + X / 4, and when x is [- 3, - 1], there is n
Is the title right? When x > 0, f (x) = x + X / 4, why not write f (x) = 5 / 4x
If it's true, the answer is 5 / 2
f(x)=x+x/4???
Have you made a mistake
Is it x + 4 / x
When x > 0, the mean value inequality is used to get
F (x) = x + 4 / x > = 2 radical (x × (4 / x)) = 4
When x = 4 / x, x = 2, the minimum value of F (x) is 4
And f (1) = 1 + 4 = 5, f (3) = 3 + 4 / 3 = 13 / 3
So in the interval [1,3], there are: 4=
The sum of the sum, difference, product and quotient obtained by adding, subtracting, multiplying and dividing an integer with itself is 121
Given that a divided by B = 3..... 5 (a x4) divided by B = 14, what is the number of a
Let this number be X
An integer is added to itself by 2x
An integer subtracts 0 from itself
An integer multiplies itself by X * X
An integer divides itself by one
The sum of sum, difference, product and quotient is 121
2x+0+x*x+1=121
(2+x)*x=120
x=10
A positive integer is 10, and a negative one is unknown