Is gerund the subject and predicate verb singular Sending emails () waste of time! Is or are?

Is gerund the subject and predicate verb singular Sending emails () waste of time! Is or are?

Gerund is a verb plus ing form, belongs to abstract noun, and can't count, so the verb predicate should use singular form
I'm going to use is here
Is the predicate verb singular or plural when two or more gerund phrases are used as subjects
for example
Watching TV and reading books are really interested
When two or more gerund phrases are juxtaposed as subjects, is the predicate singular or plural? It depends on whether the narrative is one thing or more. If it is one thing, the predicate is singular. If it is two things, the predicate is plural
Going to bed early and getting up early is a good bit
Watching TV and reading books are really interesting.
It just depends.
The number of bread and butter can only be singular
So to speak
If the maximum value of function 2x ^ 3-3x ^ 2-12x + m on [0,3] is 5, then M=
I got f '(x) = 0, x = - 1 or x = 2
The two endpoints are 0.3. What should we do next=
-1 is not in the interval, not considered
Zero
Define a factorial function, input three positive integers a, B, C from the keyboard, and calculate a! / (b! + C!) through function call
#include
int swap(int n)
{
int i,s=1;
for(i=2;i
Find the maximum and minimum of function y = 2x3-3x2-12x + 5 on [0, 3]
Let ∵ f ′ (x) = 6x2-6x-12, let ∵ f ′ (x) = 6x2-6x-12 = 0, obtain x = - 1 or x = 2, and the list is as follows: x0 (0,2) 2 (2,3) 3F ′ (x) - 0 + F (x) 5 decreasing minimum - 15 increasing - 4, so the decreasing interval of function y on [0,3] is [0,2], increasing interval is [2,3], so the minimum value of function y on [0,3] is - 15, the endpoint values are 5, - 4, so the maximum value of function y on [0,3] is 5 The minimum value is - 15
Create a function to calculate the factorial of an integer
int func(int num)
{
int result = num;
int i;
for ( i = num - 1;i>0;i--)
{
result = result * num;
}
return result;
}
The function y = 2x ^ 3 + 3x ^ 2-12x-1 increases in the interval [0,2], decreases in the interval maximum and minimum?
Y = 2x ^ 3 + 3x ^ 2-12x-1y '= 6x & # 178; + 6x-12 = 6 (X & # 178; + X-2) = 6 (x + 2) (x-1) let (x + 2) (x-1) = 0, the solution is x = - 2 or x = 1. When - 20 is increasing, so the decreasing interval [0,1] is decreasing. When the minimum value of [1,2] is x = 1, y = 2 + 3-12-1 = - 8, the minimum value is - 8. When x = 0, y = - 1, when x = 2, y = 16 + 1
y'=6x²+6x-12=6(x+2)(x-1)
(1) When 0 ≤ x ≤ 1, y '≤ 0, so the function decreases on [0,1];
(2) When 1 ≤ x ≤ 2, y '≥ 0, so the function increases on [1,2];
Therefore, the increasing interval is [1,2], and the decreasing interval is [0,1]
y(0)=-1，y(1)=-8，y(2)=3
So the maximum value on [0,2] is 3 and the minimum value is - 8
Have a good time! Hope to unfold
y'=6x²+6x-12=6(x+2)(x-1)
(1) When 0 ≤ x ≤ 1, y '≤ 0, so the function decreases on [0,1];
(2) When 1 ≤ x ≤ 2, y '≥ 0, so the function increases on [1,2];
Therefore, the increasing interval is [1,2], and the decreasing interval is [0,1]
y(0)=-1，y(1)=-8，y(2)=3
So the maximum value on [0,2] is 3 and the minimum value is - 8
Have a good time! Hope to help you, if you do not understand, please ask, I wish learning progress! O(∩_ ∩ o ∩ put away
What is the factorial of 0
It is simple to say that it is stipulated, but it is reasonable. Why not stipulate 0! = 0? Because factorial is a recursive definition, n! = n * (n-1)!, then there must be an initial value that needs to be specified artificially. We know that 1! = 1, according to 1! = 1 * 0, so 0! = 1 instead of 0
Finding the maximum and minimum of function f (x) = x3-3x + 5
f'(x)=3x²-3
Let f '(x) = 0, the solution is x = 1 or x = - 1
Let f ('x) > 0, the solution is x > 1 or X
What is the factorial of 0=
One