The coordinates of the intersection a of the image of the linear function y = - 3x + 3 and the X axis are (), and the coordinates of the intersection B of the linear function y = - 3x + 3 and the Y axis are (), S

The coordinates of the intersection a of the image of the linear function y = - 3x + 3 and the X axis are (), and the coordinates of the intersection B of the linear function y = - 3x + 3 and the Y axis are (), S

The coordinates of the intersection point a of the image of the linear function y = - 3x + 3 and the X axis are (1,0), and the coordinates of the intersection point B of the linear function y = - 3x + 3 and the Y axis are (0,3),
a(1,0)b(0,3)
1. X-axis intersection (- B / 3,0), Y-axis intersection (0, b), s = (B / 3) * B / 2 = 24, B = 12 or - 12, X-axis intersection (2,0), Y-axis intersection (0, - 3), s = (2 * 3) / 2 = 3
Let a = {(x, y) / x + 3Y = 7} and B = {(x, y) / X-Y = - 1}, then a intersects B=
The set is a point set. Solve the system of equations x + 3Y = 7, X-Y = - 1, and the solution is x = 1, y = 2. The intersection is (1,2)
To solve the quadratic equation of two variables:
x+3y=7
x-y=-1
The solution is x = 5 / 2, y = 3 / 2
So a crosses B = (5 / 2,3 / 2)
Column equation
X+3y=7
X-y=-1
If the image of y = 3x + 1 intersects with y axis at point a, the image of y = 3x-b intersects with y axis at point B, and ab = 2, then the intersection coordinates of the linear function y = 3x-b and X axis are
thank you!
The answer above is wrong! The slopes of the two straight lines are the same, so it is easy to calculate that the value of B is 1 or - 3, so the intersection coordinates of the X axis of a function rain should be (1 / 3,0) or (- 1,0)
(- 1.0) or (1 / 3.0)
(- 7 / 3, 0) or (5 / 3, 0)
Given the set a = {y y = 2-x (to the - x power of 2), X ＜ 0} and the set B = {x y = X1 / 2 (to the 1 / 2 power of x)), what is the intersection of a and B?
Given the set a = {y y = 2-x (to the - x power of 2), x < 0} and the set B = {x y = X1 / 2 (to the 1 / 2 power of x)), then what is the intersection of a and B?
A = {y y = 2-x (to the - x power of 2), x < 0}
therefore
A={y|y>1}=(1,+∞）
B={X|X>=0}=[0,+∞）
therefore
A intersection B = a = (1, + ∞)
Set a = {y y = 2-x (the - x power of 2), x < 0} = {y | Y > 1}
Set B = {x y = X1 / 2 (1 / 2 power of x)} = {x | x > = 0},
Then, a intersects B = {x | x > 1}
Set a is a set greater than 1, and set B is a set with x > 0, so all the intersection numbers are greater than 1
The coordinate of the intersection point of the image and the X axis of the linear function y = 3x + 4 is___ The coordinate of the intersection point with the Y axis is_______
The coordinates of the intersection of the image with the x-axis and the Y-axis of the linear function y = 3x + 4 are (- 4 / 3,0) and (0,4)
Complete set u a = {x | x square > 4} B = {x | x > 3} finding the intersection and union of a and B
A = {x | x2}, union = a, intersection {x | x > 3}
A = {x | x2}, B = {x | x > 3}
Then a ∩ B = {x | x > 3}, a ∪ B = {x | x2}.
The answer is not very detailed. I hope it will help you.
The value of K can be obtained on the x-axis by the intersection of the image of the first-order function y = KX + 3 and y = 3x + 6
Do X in these two relations represent a value? Let's first set y = 3x + 6, y = 0, then find x = - 2, and then substitute y = KX + 3, k = 1.5. Is that right? If not, explain why x is a value here
Since the former satisfies the relation between two points, then the latter satisfies the relation between two points
Given the set a = {1,2,3,4}, B = {x | x square-x-6 = 0}, find the intersection B and union B of A
The solution is x ^ 2-x-6 = 0
We get (x-3) (x + 2) = 0
The solution is x = 3 or x = - 2
So B = {3, - 2}
So a intersects B = {3}
A and B = {- 2,1,2,3,4}
(x-3)(x+2)=0
So B = {3, - 2}
So a ∩ B = {3}
A∪B={1,2,3,4，-2}
Solution B = {3, - 2}, a intersection B = {3}, a union B = {- 2, 1, 2, 3, 4}
How many quadrants does the image of linear function y = - 3x-2 not pass through
Not through a quadrant
First image limit
Not through the first quadrant
The known set a = {x A-1
Is equal to an empty set
If a intersects B = an empty set, then:
(1) If a is an empty set, then A-1 > = 2A + 1 and A-2 are obtained
A-1 > = 1 or 2A + 1 = 2 or - 2
First, a-1-2;
There is no intersection between a and B, either the upper limit of a is smaller than the lower limit of B, or the upper limit of B is smaller than the lower limit of A.
1) The upper limit of a is smaller than the lower limit of B: 2A + 1