Let's divide the square of x-3x + 2 / X-1,

Let's divide the square of x-3x + 2 / X-1,

(x^2-3x+2)/(x^2-1)
=[(x-1)(x-2)]/(x-1)(x+1)
=(x-2)/(x+1)
Please accept if you are satisfied. Thank you~
x-4x-5=0 x(x-2)=3x-6
Process or answer
The formula of changing base of logarithm
The bottom changing formula is an important formula, which is used in many logarithm calculation, and it is also the focus of high school mathematics. Log (a) (b) represents the logarithm of B with a as the base. The so-called bottom changing formula is log a B = log (n) (b) / log (n) (a) edit the derivation process of the bottom changing formula in this paragraph
If x ^ 2 + 4x-4 = 1, find the value of - 3x ^ 2-12x + 5
∵x^2+4x-4=1
∴x^2+4x=5
-3x ^ 2-12x is the expansion of its - 3
That is = 5 ^ (- 3) = - 15
∴-3x^2-12x+5=-15+5=-10
(x+5)(x-1)=0
x=-5,x=1
Just insert it
The solution equation is 4x + 3 = 3x + 9
 
What is the meaning of logarithm's formula of changing base
The logarithm of base n m is equal to the reciprocal of the logarithm of base n M
That is logn (m) = 1 / logm (n)
If x2 + 4x-4 = 0, then 3x2 + 12x-5=______ .
∵ x2 + 4x-5 = 0, ∵ x2 + 4x = 5, ∵ 3x2 + 12x-5 = 3 (x2 + 4x) - 5 = 3 × 4-5 = 7
X ^ 2-2x-2 = 0, 2x ^ 2 + 3x-1 = 0, 2x ^ 2-4x + 1 = 0, x ^ 2 + 6x + 3 = 0. There are three equations in which the coefficients of the first term have common characteristics. Question: 1, please use algebra
X ^ 2-2x-2 = 0, 2x ^ 2 + 3x-1 = 0, 2x ^ 2-4x + 1 = 0, x ^ 2 + 6x + 3 = 0. Among them, the coefficients of the first term of three equations have common characteristics. Q: please use algebraic expression to express this characteristic and deduce the root formula of quadratic equation with one variable
For the equation x & # 178; - 2x-2 = 0, 2x & # 178; - 4x + 1 = 0, X & # 178; + 6x + 3 = 0, the coefficient of the first term is an even multiple of the coefficient of the second term. For the first equation, the coefficient of the first term is - 2 times of the coefficient of the second term. For the second equation, the coefficient of the first term is - 2 times of the coefficient of the second term. For the third equation, the coefficient of the first term is the coefficient of the second term
Common features: the coefficient of the first term is even, set as 2p
The root formula of the equation AX ^ 2 + 2px + C = 0 (a ≠ 0) 1
Transform ① into a (x + P / a) ^ 2 = P ^ 2 / a-c
(x+p/a)^2=(p^2-ac)/a^2
The root formula is x = 1 / a [- P ± √ (P ^ 2-ac)] (P ^ 2-ac ≥ 0)
What is the logarithm formula of changing base?
log(a)b=log(s)b/log(s)a
The base number is in brackets
Let log (s) B = m, log (s) a = n, log (a) B = R
Then s ^ m = B, s ^ n = a, a ^ R = B
That is, (s ^ n) ^ R = a ^ R = b
s^(NR)=b
So m = NR, that is r = m / N, log (a) B = log (s) B / log (s) a
loga(N)=logb(N)/logb(a)
Where loga (n) denotes the logarithm of n with a as the base
If x2 + 4x-4 = 0, then 3x2 + 12x-5=______ .
∵ x2 + 4x-5 = 0, ∵ x2 + 4x = 5, ∵ 3x2 + 12x-5 = 3 (x2 + 4x) - 5 = 3 × 4-5 = 7