Given that the image of positive scale function y = ax intersects with the image of inverse scale function y = (6 + a) / X at two points a and B, 2 of the abscissa of point a, find the coordinates of points a and B

Given that the image of positive scale function y = ax intersects with the image of inverse scale function y = (6 + a) / X at two points a and B, 2 of the abscissa of point a, find the coordinates of points a and B

A = 2, B = B (- 2, - 4) brings 2 into X
Let {y = | - 3, y = | - a}
A=｛y|y=x²-2x-3｝,
y=(x-1)²-4≥-4
A=[-4,+∞）
B=｛y|y=-x²-2x-3｝
y=-(x+1)²-2≤-2
B=(-∞,-2]
therefore
A∩B=[-4,-2]
A∪B=R
Given that the positive scale function y = ax and the inverse scale function y = BX have no intersection point in the same coordinate system, then the relationship between a and B is______ .
If the positive scale function y = ax and the inverse scale function y = BX have no intersection in the same coordinate system, then the relationship between a and B is different
Given the set a = (Y / y = - x ^ + 2x-1), B = (Y / y = 2x + 1), find the intersection of a and B
y=-x^2+2x-1=-(x-1)^2
Draw the images of y = - x ^ + 2x-1 and y = 2x + 1 in the same coordinate system, and take the intersection part as the set
In the same rectangular coordinate system, the teacher drew an image of an inverse scale function and an image of a positive scale function y = - X. please observe the characteristics of the function and give us some suggestions
Student a: there are two intersections with the straight line y = - x; student B: the product of the distance from any point on the image to the two coordinate axes is 8. Please write the analytical formula of the inverse proportion function according to the above information
The inverse scale function can be set as y = K / X
From "classmate a: there are two intersections with the straight line y = - X", we can get that K is less than 0
From "classmate B: the product of the distance from any point on the image to the two coordinate axes is 8", we can know that k = - 8
So: y = - 8 / X
Calculation of (2x + y) (3x-2y) process
(2x+y)(3x-2y)
=2x*3x+y*3x-2x*2y-y*2y
=6xx+3xy-4xy-2yy
=6xx-xy-2yy
(2x+y)(3x-2y)
=2x*3x-2x*2y+y*3x-y*2y
=6x²-4xy+3xy-2y²
=6x²-xy-2y²
In the same coordinate system, draw the image of a positive scale function y = - X and an inverse scale function
A: there are two intersections with the straight line y = - X,
B: the product of the distances from any point on the image to the two coordinate axes is 5
Please write down the inverse proportion function according to the two students
It can be seen from a that the inverse proportion function can be set as: y = K / x.k > 0
It can be seen from B that xy = 5
Then k = 5
The inverse scale function is y = 5 / X
Calculation: (2x-y) (2x + y) - (3x-2y) (- 3x-2y)
：(2x-y)(2x+y)-(3x-2y)(-3x-2y)
=4x²-y²-(4y²-9x²)
=13x²-5y²
Given that the image of inverse scale function y = K / X intersects with the image of positive scale function y = - 1 / 2x and the abscissa of point a is 4, the expression of inverse scale function is?
y=k/x
y=-1/2 x
So K / x = - 1 / 2 X
x^2=-2k
Because x = 4
So 16 = - 2K
k=-8
y=-8/x
If we take a (4. - 2) in, we can find K
Two functions have intersection point a, and abscissa of point a is 4, that is, when x = 4, y value is the same, with the equation K / 4 = - 1 / 2 * 4, k = - 8 can be calculated, and the expression of inverse proportion function is y = - 8 / X
There is such a question: "calculate the value of (3x ^ 3-3x ^ 2y-4xy ^ 2) - (2x ^ 3-4xy ^ 2 + y ^ 3) + (- x ^ 3 + 3x ^ 2y-y ^ 3), where x = 6, y = - 1." student a mistakenly copied "x = 6" into "x = - 6", but his calculation result is also correct. What do you think of this?
Original formula = 3x ^ 3-3x ^ 2y-4xy ^ 2-2x ^ 3 + 4xy ^ 2-y ^ 3-x ^ 3 + 3x ^ 2y-y ^ 3
Merge the same type
=-2y^3
There is no X in the result
So x is wrong, and it doesn't affect the results
As soon as you dissolve, you're left with y, regardless of X