(3x-2) (3x-2) - 3x + 2 = 0 using factorization

(3x-2) (3x-2) - 3x + 2 = 0 using factorization

(3x-2)(3x-2)-3x+2=0
(3X-2)^2-(3x-2)=0
(3x-2)(3x-2-1)=0
(3x-2)(3x-3)=0
3x-2=0,3x-3=0
x=2/3,x=1
(3x-2)(3x-2)-3x+2=0
(3x-2)(3x-2)-(3x-2)=0
(3x-3)(3x-2)=0
(3x-3) = 0 or (3x-2) = 0
X = 1 or 2 / 3
How to solve the equation 3x0.7 + 4x = 6.5
4x=6.5-3x0.7
4x=4.4
X=1.1
3x0.7+4x=6.5
2.1+4x=6.5
4x=6.5-2.1
4x=4.4
x=4.4/4
x=1.1
I don't understand your equation. Can you be more detailed
4x=6.5-3*0.7
4x=6.5-2.1
4x=4.4
x=4.4/4
x=1.1
Advanced expression of Coulomb's law
Just look at the textbooks of China University of science and technology
Using factorization to solve the power of (x + 1) - 3x (x + 1) = 0
Same as above, kneel down, to detailed process, said very do not understand the method of doing this kind of problem~~~
To do this kind of problem, you need to use factorization skillfully,
Extracting common factor is the most basic method, and square difference and complete square formula are often used
(x+1)^2-3x(x+1)=0
(x+1)(x+1-3x)=0
(x+1)(-2x+1)=0
So X1 = - 1, X2 = 1 / 2
If satisfied, please accept
4X + 5 × 8 = 72, the solution of this equation is 28______ .
According to the meaning of the question, substituting x = 28 into the original equation, we can get: left = 4 × 28 + 5 × 8 = 112 + 40 = 152; right = 72; left ≠ right; therefore, x = 28 is not the solution of the original equation
Physics problems on Coulomb's law
Two metal balls a and B, which can be regarded as particles, have mass m with + Q point load. Use a rope to put the two balls up and hang them on a board. A is on the top of B, and the top of the lower rope is o. the rope is divided into OA section and AB section. What is the tension of AB thin line? What is the tension of OA thin line
The answer is that ab segment is Mg + F, AB is regarded as the whole Coulomb force, and OA segment is 2mg
Why do we take AB as a whole to find the OA segment? I think if we don't take AB as a whole, the OA segment is equal to 2mg-f. if we take AB as a whole, the force of which ab segment is not mg is not the answer
The answer you're talking about is a holistic approach
In the following analysis, the isolated Coulomb force is used
For B, B is under the Coulomb force of gravity
So Mg + F = T1
The Coulomb force of a under gravity
Mg+T1=T2+F
T2=Mg+T1-F=2Mg
By using formula method, the following polynomials are factorized: - 4x & sup2; + (2x-3y) & sup2;
=(2x-3y)^2-4x^2
=(2x-3y)^2-(2x)^2
=(2x-3y+2x)(2x-3y-2x)
=-3y(4x-3y)
The square difference formula is used
Please make it clear. I can't understand it
The solution of equation (12x-1) (6x-1) (4x-1) (3x-1) = 5 is
x1=1/2
x2=-1/12
Application of Coulomb's law in Physics
There are three particles ABC, whose distance is l, and the charge of a and B are 10q and Q respectively. Now a constant force F is applied at C, and the three points still move with the distance L. find the size of F and the charge of C
Figure: a --- (L) --- B --- (L) --- C
This is a typical question, and there are a lot of data. It is necessary to make an overall analysis and isolation analysis, and also apply it to the Niu Er Ding of senior one
6x-48 = 4.5X + 27 5x-6 = 4 (x + 2) + 4 22 times 4 + (x-22) times 2 = 3x + 2 the process of solving the above equation, thank you for helping me quickly = v=
27 Where separation is a problem 4 where separation is a problem
6X-48=4·5X+27
1.5x=75
x=50
5X-6=4(X+2)+4
5x-6=4x+12
x=18
22*4+(x-22)*2=3x+2
2x+44=3x+2
x= 42
6X-48=4·5X+27
1.5X=75
X=50
5X-6=4（X+2)+4
5X-4X=8+4+6
X=18
22 times 4 + (x-22) times 2 = 3x + 2
88+2X-44=3X+2
2X-3X=2-88+44
-X=-42
X=42
6X-48=4·5X+27
1.5x=75
x=50
5X-6=4(X+2)+4
5x-6=4x+12
x=18
22*4+(x-22)*2=3x+2
2x+44=3x+2
x= 42