(1) Given a + B = 4, a & # 178; - B & # 178; = 24, then a = B= （2）36-x² （3）-1+25x² （4）（x+y）²-x² (5) The following polynomials cannot be factorized by the square difference formula A. 1 / 4m & # 178; n & # 178; - 1 B. - 0.25 + x 4 power C. - 1-x & # 178; D. - A & # 178; + 1

(1) Given a + B = 4, a & # 178; - B & # 178; = 24, then a = B= （2）36-x² （3）-1+25x² （4）（x+y）²-x² (5) The following polynomials cannot be factorized by the square difference formula A. 1 / 4m & # 178; n & # 178; - 1 B. - 0.25 + x 4 power C. - 1-x & # 178; D. - A & # 178; + 1

1. A & # 178; - B & # 178; = (a-b) (a + b) a + B = 4, A-B = 6A = 5, B = - 12. (6-x) (6 + x) 3. (5x-1) (5x + 1) 4. (x + Y-X) (x + y + x) = y (2x + y) 5. C-1-x & # 178; = - (1 + X & # 178;) square difference formula: (a + b) (a-b) = a ^ 2-B ^ 2
Solve the equation 3x + 3.3 = 7.922.5 × 8-2x = 12 1 / 2 × (x + 1) = 3 / 4 3 / 4x-0.05x = 17.5
solve equations
3X+3.3=7.92
2.5×8-2X=12
1/2×（X+1）=3/4
3/4X-0.05X=17.5
(1) 3x + 3.3 = 7.923x = 7.92-3.33x = 4.62x = 1.54 (2) 2.5 * 8-2x = 122x = 20-122x = 8x = 4 (3) 1 / 2 (x + 1) = 3 / 4x + 1 = 3 / 2x = 1 / 2 (4) 3 / 4x-0.05x = 17.53 / 4x-1 / 20x = 17.515x-x = 35014x = 350x = 25
Quick return
What is the formula for changing the base of logarithmic function, such as loga (b) = xlogb (a), then x =?
x=loga(b)/logb(a)=[logb(b)/logb(a)]/logb(a）=1/[logb(a)]²
The formula of logarithm changing base is to change the original base into another base when it is not satisfied with the original base, and the result is a fraction; the base of numerator denominator is the same,
The two real numbers are the original two numbers in the original position. The original real number is on the top, and now it is still on the top. The original bottom is the real number, making the real number in the logarithm of the denominator at the bottom;
loga(b)=[logc(b)]/[logc(a)]
Factorize the following equation: 3x square - 9x + 8 = 0
3x²-9x+8=0
3x -4
x -2
That is, (3x-4) (X-2) = 0
x1=4/3 x2=2
The equation of degree b-4ac = 81-96 ＜ 0 has no real root
How to solve the equation 3x + 5 (X-2) = 30?
3x+5(x-2)=30
3x+ 5x - 10 = 30
8x = 40
x = 5
The evaluation of mathematics in grade one of senior high school with the formula of changing bottom
2lg5/lg2 - 6lg2/lg5
Hope to see this problem
People who can do it
Be more efficient
Tell me earlier
=2 (log2 5)-6 (log5 2)
=2 (1/(log5 2))-6 (log5 2)
I think so
The square of (7a-8b) - the square of 4x
The square of solution (7a-8b) - the square of 4x
=（7a-8b）²-4x²
=（7a-8b）²-（2x）²
=（7a-8b+2x）（7a-8b-2x）
49A ^ 2-112ab + 64b ^ 2-16x ^ 2
1.3x + X-30 = 200 (how to solve this equation)
Urgent!
2.3x=230
x=230/2.3
x=100
How to use the formula of changing bottom
I'm very stupid. I can't use the formula of changing bottom. For example, log15 (20) = log3 (20) / log3 (15). Why? How did 3 come out? Can you give me an example,
This 3:00 random, you see what number for their own convenience to take whatever
The original formula is logm (n) = loga (n) / loga (m) (a > 0 and a is not 1)
For example, s = log2 (3) * log3 (4) * log4 (5). Log2009 (2010)
The formula log2 / log3 = 10 is used directly
log3(4)=log10(4)/log10(3)
.
log2009(2010)=log10(2010)/log10(2009)
The above formula is directly related to each other
=〉s=log2(3)*log3(4)*log4（5）.log2009(2010)
=log10(3)/log(2)*log10(4)/log(3)...log10(2010)/log10(2009)
=log10(2010)/log10（2）
=log2(2010)
You should find that the above calculation is the same without taking 10 as the base, but sometimes you need to take a specific number yourself
Factorization (3a-7b) (7a-7a) + (1b-7a)
It's a process
=(7a-8b)[(3a-4b)+(11a-12b)]
=(7a-8b)(3a-4b+11a-12b)
=(7a-8b)(14a-16b)
=2(7a-8b)²