X2-5x-2001 = 0, then (X-2) ^ 3 - (x-1) ^ 2 + 1 =? Title, such as

X2-5x-2001 = 0, then (X-2) ^ 3 - (x-1) ^ 2 + 1 =? Title, such as

Cappuccino Sa: ∵ x ^ 2-5x-2001 = 0 ∵ x ^ 2-5x = 2001 [(X-2) ^ 3 - (x-1) ^ 2 + 1] / (X-2) = (X-2) ^ 2 - [(x-1) ^ 2-1] / (X-2) = x ^ 2-4x + 4 - (x ^ 2-2x) / (X-2) = x ^ 2-4x + 4 - [x (X-2) / (X-2)] = x ^ 2-4x + 4-x = x ^ 2-5x + 4 = 2001 + 4 = 2005
Recursive formula for general term formula
There is a recurrence formula
a(n)=2a(n-1)+2^(n-1)
Can we also use the recurrence formula which is constructed as an equal ratio sequence
b(n)=qb(n-1)
To construct (the beginning of an equation) as a ratio
To find the general term formula?
tolerable
Let BN = an / 2 ^ n, divide both sides of a (n) = 2A (n-1) + 2 ^ (n-1) by 2 ^ n at the same time
bn=2b(n-1)+1/2
bn-1/2=2(b(n-1)-1/2）
Let CN = bn-1 / 2, then CN = 2C (n-1), that is {CN} is an equal ratio sequence, then the general term of CN can be obtained, and the general terms of BN and an can be obtained by substitution
Solution to equation. 116: x = 512 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & 34x-5% x = 17.5
（1）116：x=512，             5x=116×12，          5x÷5=14÷5，    &...
1*2/5x+2*3/5x+3*4/5x+4*5/5x+...+2003*2004/5x+2004*2005/5x=1
5x(1-1/2+1/2-1/3+...1/2003-1/2004+1/2004-1/2005)=1
5x×（1-1/2005)=1
5x×2004/2005=1
x=401/2004
On vector formulas, urgent,
I just know that if a vector multiplied by B vector is equal to zero, then a vector will be perpendicular to B vector. Then a vector multiplied by negative B vector, is it still vertical? Because I think a selection item is intersecting but not vertical, I think it seems right. This topic will be handed in tomorrow, please brothers and sisters!
The product of vectors is only the vector module times the angle
And loud positive and negative only affect the direction, not the size
You can change your mind,
When vector a is multiplied by vector B and so on, it means that cos ∠ is equal to 0,
When the sign is added in the front, in the range of 0 to π, it is still ∠ equal to 90
So I think it's still vertical
If the vectors a and B are not zero vectors, then a times b equals zero or a times negative B equals zero can ensure that the two vectors are perpendicular to each other. These two are equivalent
Because a * (- b) = - (a * b) = 0
So a * b = - 0 = 0
So a is perpendicular to B
I think it's easier to understand the formula. The product of vectors is only the vector module multiplied by the angle. A * - B = (a) (b) cos @ (their angle), because a and B vectors are always vertical, and B and - B vectors are only in the opposite direction, the angle is 90, so cos90 = 0, a * - B = 0, can only be vertical
4X = 11 / 12 solution equation
Is that 21
4x=11/12
12*4x=11
48x=11
x=11/48
4X = 11 / 12
107x/5=11/12
x=55/1284
x=11/12&(214/100)
Solution equation: 3x + 8 = 5x-6x (3x + 2) - x = 21880 + x = 3 (52-x)
3X+8=5X-6X
4x＝-8
x＝-2
（3X+2）-X=218
2x+2=218
2x=216
x=108
80+X=3（52-X
80+x=156-3x
4x=156-80=76
x=19
X equals minus 2108, 19
Hyperbola, the focus on the x-axis C = 6, and through the point (- 5,2), hyperbolic equation
Please help me, I can't figure it out
b^2=c^2-a^2=36-a^2
Since the hyperbolic focus is on the x-axis, let the hyperbolic equation be
x^2/a^2-y^2/(36-a^2)=1
Substituting (- 5,2) into hyperbolic equation
25/a^2-4/(36-a^2)=1
25(36-a^2)-4a^2=36a^2-a^4
900-25a^2-4a^2=36a^2-a^4
a^4-65a^2+900=0
A ^ 2 = 45 (abandon, a ^ 2 must be less than C ^ 2), a ^ 2 = 20
b^2=c^2-a^2=16
So the hyperbolic equation is
x^2/20-y^2/16=1
No solution?
Solve the equation (4.4x = 17.4x) *!
4x+0.25=5.8
4x=5.55
x=1.3875
（4x+0.25)*3=17.4
4x+0.25=17.4/3
4x+0.25=5.8
4x=5.8-0.25
4x=5.55
x=1.3875
（4x+0.25)*3=17.4
4x+0.25=17.4/3
4x+0.25=5.8
4x=5.8-0.25
4x=5.55
x=1.3875
12x+0.75=17.4
12x=16.65
x=1.3875
solve equations:
（4x+0.25)*3=17.4
12x+0.75=17.4
12x=16.65
x=1.3875
x=1.3875
(4x+0.25)*3=17.4
12x+0.75=17.4
12x=16.65
x=1.3875
x=(17.4/3-0.25)4
x=1.3875
X=1.3875
Given that (3x + 1) (x-1) - (x + 3) (5x-6) = x2-10x + A, then a=____
2 is the square
A=-3X^2-21X+17