It is known that the solution set of the inequality system ax & # 178; + BX + C > 0 about X is C < x < 2, and the solution set of the inequality system CX & # 178; + BX + a > 0

It is known that the solution set of the inequality system ax & # 178; + BX + C > 0 about X is C < x < 2, and the solution set of the inequality system CX & # 178; + BX + a > 0

The solution set of the inequality system ax & # 178; + BX + C > 0 of X is C < x < 2,
So A0
That is, the solution with a (1 / x) ^ 2 + B (1 / x) + C > 0 is C
ax^2+bx+c>0
-ax^2-bx-c
If the solution set of inequality ax & # 178; + BX + 2 = 0 is 1 / 3 < x < 1 / 2, then a + B=
Ax & # 178; + BX + 2 = 0 are 1 / 3 and 1 / 2
Given that the solution of inequality ax & # 178; + BX + C is - 2 ≤ x ≤ 3, then the solution of inequality CX & # 178; + BX + A is?
If the solution of ax & # 178; + BX + C > 0 is - 2 ≤ x ≤ 3, then the solution of inequality CX & # 178; + BX + a < 0 is?
-1 / 2 ≤ x ≤ 1 / 3 from the solution, we can know that C / a = - 6, C = - 6a, formula - B ± √ (b ^ 2-4ac)) / (2a) we can know that the root of these two inequalities is a multiple of one sixth, and the direction of AC is opposite, the direction of two inequalities is opposite, then we can know that the direction of solution is the same, so the multiple of negative two and negative one sixth of three is
How to get the formula of circumference and area of a circle?
The circle is divided into several small sectors, and then the sectors are combined into rectangles, which are obtained according to the algorithm of perimeter and area of rectangles
1. We have known the system of equations about X. Y: x + y = 5m. X-Y = 9m, the solution of which satisfies 3x + 2Y = 17, then M=_______
x+y=5m.
x-y=9m
>
Subtraction,
2y=-4m
y=-2m
x=7m
3x+2y=17
21m-4m=17
M=1
Simultaneous x + y = 5m. X-Y = 9m
The solution is x = 7m, y = - 2m
Substituting 3x + 2Y = 17
21m-4m = 17
The solution is m = 1
x+y=5m.
x-y=9m
>
Subtraction,
2y=-4m
y=-2m
x=7m
3x+2y=17
21m-4m=17
M=1
Formula 1 + formula 2 gives x = 7m
Formula 1-2 gives y = - 2m
So 3x + 2Y = 17m = 17
M=1
M=1
First, according to the equations: x = 7m; y = - 2m
Substituting into the following equation, we get m = 1
From (1) + (2), x = 7m
From (1) - (2), y = - 2m
3X+2Y=3*7M+2*（-2M）=17M
So m = 1
x+y=5m x-y=9m 3x+2y=17
Set X + y = 5m as ① X-Y = 9m as ② two ① + the previous ② equals 3x + 2Y, so 9m + 5m + 5m = 19m = 17 m = 19 / 17
Equation: 3x (x + 2) + 2 (x + 1) (x-1) = 5 (square of X + 8)
3X(X+2)+2(X+1)(X-1)=5(X²+8)
3X²+6X+2(X²-1)=5X²+40
3X²+6X+2X²-2=5X²+40
6X-2=40
6X=42
X=62÷6
X=7
Given the complete set u = R, the set a = {x [- 1 ≤ X-1 ≤ 2}, B = {x [x-a ≥ 0, a ∈ r}, if the complement of a ∩ the complement of B = {x [x less than 0}, the complement of a ∪ B}
If the complement of set ∪ B = {x [x is less than 1 or X is greater than 3}, then what is a =
A={X[-1≤X-1≤2}
A={X[0≤X≤3}
Complement of a = complement of a ∪ complement of B = {x [x less than 1 or x greater than 3}
The complement of a ∩ the complement of B = {x [x ≤ 0}, B = {x [x ≥ a, a ∈ r}
Complement of B = {x [x ≤ a, a ∈ r}
A=0
Divide the polynomial 3x & # 178; - 2x + 3y-4xy-5-y & # 178; into two groups, the two brackets are connected with "-" and the first bracket is full of
The second bracket does not contain quadratic items
3x²-2x+3y-4xy-5-y²
=（3x²-y²-4xy）-（2x-3y+5）
A formula for calculating the area of a ring
What else is there besides S-ring = (area of big circle) - (area of small circle)?
It can also be equal to (radius of big circle + radius of small circle) x 3.1415926. (PAI)
It is known that the solution of the system of equations x + 2Y = 5m x-2y = 9m satisfies the equation 3x + 2Y = 17, and the value of M is obtained
x+2y=5m
x-2y=9m
We get x = 7m, y = - M
Substituting 3x + 2Y = 17
21m-2m=17
m=17/19
x+2y=5m
x-2y=9m
x=7m,y=-m
3x+2y=17
3*7m+2*(-m)=17
m=17/19
seventeen-nineteenths
2X=14M,X=7M
4Y=-4M,Y=-M
21M-2M=17,19M=17,M=17/19
x+2y=5m
x-2y=9m
x=7m
y=-m
Substituting x = 7m, y = - m into 3x + 2Y = 17 leads to
3*7m+2*(-m)=17
m=17/19
It can be seen from the meaning of the title:
{x+2y=5m
{x-2y=9m
The solution is y = - 7m
From x = 7m, y = - M satisfying the equation 3x + 2Y = 17, it is obtained that: 1
3*7m+2*(-m)=17
The solution is m = 17 / 19
m=17/19