The solution set of inequality (2a-b) x ＞ a-2b about X is x ＜ 52. Find the solution set of inequality ax + B ＜ 0 about X

The solution set of inequality (2a-b) x ＞ a-2b about X is x ＜ 52. Find the solution set of inequality ax + B ＜ 0 about X

From the solution of inequality (2a-b) x ＞ a-2b about X, we can get x ＜ a − 2b2a − B or X ＞ a − 2b2a − B, ∵ x ＜ 52, ∵ 2a-b ＜ 0, that is 2A ＜ B, ∵ a − 2b2a − B = 52, 2a-4b = 10a-5b, ∵ 8A = B, ∵ 2A ＜ B, that is 2A ＜ 8a, ∵ a ＞ 0, ∵ from ax + B ＜ 0, we can get x ＜ - BA, that is x ＜ - 8
If the solution set of X + AB is - 1
According to the meaning of the title, we can draw a conclusion
X + AB (enclosed in braces)
The solution, the solution
A+b
x+aa+b
Because the solution set is - 1
The solution set of group inequality system x + AB is - 1
∵x+ab
∴x＜b-a,x＞b+a
The solution set of ∵ x + AB is - 1
In the triangle ABC, the opposite sides of angle a, B and C are ABC and C = 2, C = 60 ° respectively. Find (a + b) divided by (Sina + SINB)
In the triangle ABC, the opposite sides of angle a, B and C are ABC and C = 2, C = 60 ° respectively. Find the value of (a + b) / (Sina + SINB). If a + B = AB, find the area of triangle ABC
A / Sina = B / SINB = C / sinc = 2R (sine theorem) so (a + b) / (Sina + SINB) = C / sinc = 2 / (√ 3 / 2) = 4 √ 3 / 3C & # 178; = A & # 178; + B & # 178; - 2abcos 60 ° so 4 = A & # 178; + B & # 178; - AB (1) a + B = AB (2) a = b = 2 so s = (absinc) / 2 = √ 3
C = 2, C = 60?????? is that a mistake
Do it in this way.
Using sine theorem (side a + side B) / (Sina + SINB) = 2R = side C / sinc = 2 / sin60
By using the string theorem and the conditions, we can find the area by finding side a and side B
Given I = R, let a = {X / - 1 ＜ x ＜ 2}, B = {X / 0 ≤ x ＜ 5}, then CIA ∩ CIB =? A ∪ CIB =?
A = {X - 1 < x < 2}
B = {x 0 ≤ x < 5}
Ψ CIA = {x ≤ - 1 or X ≥ 2}
CIB = {x x < 0 or X ≥ 5}
Ψ CIA ∩ CIB = {x ≤ - 1 or X ≥ 5}
A ∪ CIB = {x x < 2 or X ≥ 5}
If the polynomial 2mx & sup3; + 3nxy & sup2; + 5xy & sup3; - XY & sup2; + y contains no cubic term, the value of 2m + 3N is obtained
Original formula = 2mx ^ 3 = (3n-1) XY ^ 2 + 5xy + y
Without X3 times
Then (3n-1) = 0, n = 1 / 3
2m=0 m=0
2m+3n=0+1=1
As shown in the figure, on the horizontal ground of the construction site, there are three cement pipes with an outer diameter of 1m, which are stacked together tangentially, then the distance from the highest point to the ground is______ .
Connecting the center of each circle, we can get an equilateral triangle with side length of 1. The height of the equilateral triangle is 1 × sin60 ° = 32, then the distance from its highest point to the ground is 1 + 32 meters
2 (1-2x) = - (1 + 3x) (2x-1) + 3 (4x-7) - 5 (3x + 2) + 5 = 3x-4 of 0.2 = 1 of 2
Step by step,
Forget the space, 2 (1-2x) = - (1 + 3x) (2x-1) + 3 (4x-7) - 5 (3x + 2) + 5 = 0.2 / 3x-4 = 2 / 2x
2（1-2x）=-（1+3x） 2-4x=-1-3x,-x=-3,x=3
（2x-1）+3（4x-7）-5（3x+2）+5=0.2x-1+12x-21-15x-10+5=0,-x=27,x=-27
3x-4 / 2 = 2x.3x-8 = x, 2x = 8, x = 4
In △ ABC, a = 60 °, B = 1, and △ ABC area is 3, then the value of a + B + csina + SINB + sinc is ()
A. 2393B. 2633C. 833D. 23
∵ s △ ABC = 12bcsina = 12 × 1 × C × 32 = 3 ∵ C = 4 according to the cosine theorem: A2 = B2 + c2-2bccosa = 1 + 16-2 × 1 × 4 × 12 = 13, so a = 13 according to the sine theorem Asina = bsinb = csinc, then: a + B + csina + SINB + sinc = Asina = 2393, so choose a
It is known that the definition field of function f (x) = radical 3-x + 1 / radical x + 2 is set a, B = {x ﹤ a} (1). If a is contained in B, the value range of a is obtained
(2) If u = {x x ≤ 4}, a = - 1, find CUA and a ∩ (cub)
(1) A {x} - 2
To be honest, I can't understand your topic
From the meaning of the title
3-x≧0，x﹥0，
The solution is 0 ＜ x ≤ 3, | a = {x | 0 ＜ x ≤ 3}
∵ A is contained in B, ∵ a ≥ 3
(2) ∵ a = - 1, u = {x x ≤ 4}
Ψ B = {x x ≤ - 1}
CuA=3＜x≦4
A∩(CuB)=A=0＜x≦3