If the solution set of inequality {x + a < B, x-a > b is - 1 < x < 3, find the solution of AX + B ≤ 0

If the solution set of inequality {x + a < B, x-a > b is - 1 < x < 3, find the solution of AX + B ≤ 0

According to the meaning of the title, we can draw a conclusion
X + AB (enclosed in braces)
The solution, the solution
A+b
If a > - b > 0, the solution set of the inequality system ax > b.bx < A is ()
From a > - b > 0, the following results are obtained
a>0,b
The algebraic formula X2 - (3kxy + 3y2) + one third XY-8 does not contain x, y, find K
The term containing XY in X2 - (3kxy + 3y2) + one third of XY-8 is
-3Kxy-xy=（-3K-1）xy
Without XY, then - 3K-1 = 0
The solution is k = - 1 / 3
Simplify first, do now
The answer of the position relationship between the circle and the circle
There are five kinds of positional relations between two circles: if there is no common point, a circle outside the other circle is called exocentric and inside is called introcentric; if there is a unique common point, a circle outside the other circle is called circumscribed and inside is called inscribed; if there are two common points, it is called intersection. The distance between the centers of two circles is called center distance
There are several kinds, inscribed, circumscribed, intersected, separated. No, you can read books when you have time. This is the foundation!
Look at the mathematics book of junior three. I don't remember the details. It seems that there is something inscribed and intersected
1.d>R+r d=R+r d+r
What is a unary linear inequality about X, such as 4x-m + 1 = 3x-1
On the inequality of one variable degree of X, it means that the letter X is regarded as an unknown number, and the degree is 1, other letters are regarded as known numbers
For example, in 4x-m + 1 = 3x-1, letters are regarded as known numbers
4x-m+1=3x-1
4x-3x=-1+m-1
x=m-2
In the triangle ABC, the angles a, B and C satisfy 2sinb = Sina + sinc. It is proved that two thirds of COS (A-C) = two thirds of COS (a + C)
2sinB＝sinA＋sinC
2sin(180°-(A+C))=2sin(A+C)/2cos(A-C)/2
sin(A+C)=sin(A+C)/2cos(A-C)/2
2sin(A+C)/2*cos(A+C)/2=sin(A+C)/2cos(A-C)/2
2cos(A+C)/2=cos(A-C)/2
The solution X of lgx + LG (x + 3) = 1=
From the formula of LGA + LGB = lgab, we get LG [x * (x + 3)] = 1, so x * (x + 3) = 10, we get x = 2 or x = - 5. When x = - 5, LG (x + 3) is meaningless and should be discarded, so x = 2
When k = 0___ The algebraic formula x2-8 + 15xy-3y2 + 5kxy contains no XY term
The original formula = x2 + (15 + 5K) xy-3y2-8, because there is no XY term, so 15 + 5K = 0, the solution is: k = - 125, so the answer is - 125
As shown in the figure, there are several kinds of positional relations between circles
I will not send the picture ~ the key is not this~
I find out four kinds: circumcision, introcision, introversion and exoversion
However, our teacher said: inscribed, circumscribed calculate one: tangent; introverted, circumscribed calculate one: separation
So there are two~
Should we do this? Should we choose four or two?
The options are a, 2 B, 3 C, 4 D and 5. I don't think it's necessary to have the "C, D" option if we understand it as the teacher does
How to calculate this kind of problem?
All of them are right. Ha ha, this question is a problem, generally it should be 4 kinds
Two parts X-1 & lt; three parts 4x-5 and two parts x + 7-1 ＜ two parts 3x + 2 solve one variable linear inequality
X-1 / 2