If the system of inequalities 2x + 5A ≤ 3 (x + 2) x-a2 ≤ X3 has solutions and each solution x is not in the range of - 1 ≤ x ≤ 4, the value range of a is obtained

If the system of inequalities 2x + 5A ≤ 3 (x + 2) x-a2 ≤ X3 has solutions and each solution x is not in the range of - 1 ≤ x ≤ 4, the value range of a is obtained

2X + 5A ≤ 3 (x + 2) ① x-a2 ≤ x3 ②, from ① we get: X ≥ 5a-6; from ② we get: X ≤ 34a,  5a-6 ≤ x ≤ 34a; from the meaning of the title we get: 34a ＞ 4 or 5a-6 ＜ - 1, the solution is: a ＜ 1 or a ＞ 163
Find the integer solution of the system of inequalities 2x − 11 ＞ 0x ≤ 12x + 4
The solution of inequality 2x-11 > 0 is: x > 112, and the solution of inequality x ≤ 12x + 4 is: X ≤ 8, so the solution set of inequality is: 112 < x ≤ 8, then the integer solution is 6, 7, 8
What are the positional relationships between circles?
The radius of the two circles is R1, R2, (R1 > R2) and the center distance is d,
D > R1 + R2
Circumscribed: D = R1 + R2
Intersection: R1-R2
Disjoint tangent (inscribed and circumscribed) intersection inclusion
Apart, intersect, circumscribe, inscribe, contain
Separation, extraversion, introversion, introversion
The following equations are solved by substitution method. (1) {3x = 4Y, 4x-5y = 3 (2) {3 (x-1) = y + 1, 2 (Y-1) = 4 (x + 2)
(1) Substituting x = 4 / 3Y into 4x-5y = 3 yields x = 12 and y = 9
(2) 3 (x-1) = y + 1, we can get 3x-3 = y + 1, so y = 3x-4, and substitute 2 (Y-1) = 4 (x + 2)
The solution is x = 9, y = 23
1.X12Y9
3x = 4Y, x = (3Y) / 4, substituting 4 ((3Y) / 4-5y = 3, x = 2, y = - 1.5
Y = 3x-4, substitute 6x-10 = 4x + 8, x = 9, y = 23
Factorization of 2x & sup2; - XY + 3x-y + 1
2x²-xy+3x-y+1
=2x^2+3x+1-y(x+1)
=(2x+1)(x+1)-y(x+1)
=(x+1)(2x-y+1)
2x²-xy+3x-y+1
＝(2x²+2x)-(xy+y)+(x+1)
＝2x(x+1)-y(x+1)+(x+1)
＝(x+1)(2x-y+1)
If the complete set is a real number set R and a = {x | Log1 / 2 (2x-1) > 0}, then what is the complement of a in R?
Firstly, we solve the inequality Log1 / 2 (2x-1) > 0, that is Log1 / 2 (2x-1) > Log1 / 2 (1)
Because the base of Log1 / 2 (x) is less than 1, it is a decreasing function
So 0
-The second power of [x + 1] + the second power of 9 [X-2] + the second power of [7x + 2Y] - the second power factorization of [2x + 7Y]
Are these two questions?
－﹙x＋1﹚²＋9﹙x－2﹚²
﹙7x²＋2y²﹚²－﹙2x²＋7y²﹚²
Is the original formula like this?
On the positional relationship between circles
There is a sector with a center angle of 90 degrees, and three equal circles are circumscribed in turn, and are all inscribed with the arc of the sector. The two circles on the edge are tangent to the radius of the sector. The radius of the sector is 6cm. Try to find the radius of the small circle
The radius of the small circle is about 1.23363 cm. I have to think about the specific calculation process
It is known that each small circle occupies a sector space of 30 degrees. Let the radius of the small circle be x, then x / (6-x) = sin (30 degrees / 2). To solve this equation, we get x = (6 times root 6-6 times root 2) / (4 + root 6-root 2)
Plus six is 25
Plus six is 25
Let the radius of the small circle be r
Then R + 2rsin60 + R / tan22.5 = 6
tan22.5=√2-1
r(1+√3+√2+1)=6
r=6/(2+√2+√3)
About 1.16589 cm
If a = 4x square - 3x - 2, B = 4x square - 3 - 4, try to compare the size of a and B
A-B=4x^2-3x-2-4x^2+3x+4
=2>0
So a > b
Factorization in real numbers: 3x & # 178; - 4xy-y & # 178;
3x²-4xy-y²
=7x²-4x²-4xy-y²
=7x²-(2x+y)²
=(√7x+2x+y)(√7x-2x-y)
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