The coordinates of the center P of a circle (- 2,5), and its radius is 6, then the origin of the coordinates is at point P

The coordinates of the center P of a circle (- 2,5), and its radius is 6, then the origin of the coordinates is at point P

The distance from the center of the circle to the origin of the coordinates is root 29, which is less than 6

In the plane rectangular coordinate system, 0 is the coordinate origin, and the circle with 0 as its center is tangent to the straight line x-radical 3y-4 = 0 1. Find the circle 0 equation 2. The straight line L: y = KX + 3 and circle 0 intersect at two points A. B. whether there is a point m on circle 0, so that the quadrilateral oamb is diamond. If there is, calculate the slope of the straight line L; if not, please explain the reason

1. If the radius of the circle is r, then the tangent result is: the distance from o point to the straight line X - √ 3y-4 = 0 = R; | 0 - √ 3 × 0-4 / √ (1 + 3) = R; r = 2, so the equation of the circle is: x ﹣ y ﹤ 4; 2

O is the coordinate origin, and the coordinate of a is (1, root 3) 1: A reward of 100 seconds is offered: O is the origin of coordinates, the coordinate of a is (1, the root 3), M is the point on the coordinate axis, and the triangle MOA is an isosceles triangle. How many points meet the conditions? A4 B5 C6 D8

Six were (- 2,0) (2,0) (0,2) (0, - 2) (0,2 √ 3 / 3) (0,2 √ 3)
OA = OM, OA = am, OM = am, three cases are OK

It is known that an ellipse in a plane rectangular coordinate system has its center at the origin and its left focus is f (- Set point a (1, 1) through D (2, 0) 2). (1) Find the standard equation of the ellipse; (2) If P is a moving point on an ellipse, the trajectory equation of point m in line PA is obtained

(1) ∵ for an ellipse in a plane rectangular coordinate system, its center is at the origin, the left focus is f (- 3, 0), and through D (2,0), ᙽ the semimajor axis of the ellipse a = 2, the half focal length C = 3, then the semi minor axis B = 1.

In the plane rectangular coordinate system, if the focal length of the ellipse x ^ 2 / A ^ 2 + y ^ 2 / b ^ 2 = 1 (a > b > 0) is 2, the circle with o as the center and a as the radius, and the two tangent lines of the circle passing through the point (a ^ 2 / C, 0) are perpendicular to each other, then the eccentricity e = It's better to have a detailed solution. It's not possible to get a number of answers The title was given to me. I don't know right or wrong, but thank you

The problem is right. It's easy to draw a picture
∵a√2=a^2/c
∴c/a=1/√2=√2/2=e

In the plane rectangular coordinate system, the relationship between the position of point B (1,4) and the circle with (2,3) as its center and 2 as its radius

See the center distance and radius
(2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) = (2) = (

In the plane rectangular coordinate system, Xiao Fang draws a circle with point a (0, - 3) as its center and 3 as its radius

The equation of a circle
x²+(y+3)²=9
When x = 0
(y+3)²=9
Y + 3 = 3 or y + 3 = - 3
Y = 0 or y = - 6
So the intersection with the Y axis is (0,0) and (0, - 6)
In fact, it's OK to do it directly,
Let the intersection point (0, m)
Then | m + 3 | = 3
M = 0 or M = - 6
So the intersection with the Y axis is (0,0) and (0, - 6)

In a rectangular coordinate system, a circle is drawn with (0,4) as its center and 3 as its radius As above

(0,7) (0,1) kindergarten questions

Draw ⊙ B with B (0,3) as the center and 6 as the radius to find the intersection coordinates of the circle and the coordinate axis

Because B (0,3) is the center of the circle and the radius is 6
So the equation of circle B is: x ^ 2 + (Y-3) ^ 2 = 36
When x = 0, (Y-3) ^ 2 = 36, y = 9 or y = - 3
When y = 0, x ^ 2 = 36, x = 6 or x = - 6
So the coordinates of the intersection of the circle and the axis are
(0,9) (0,-3) (6,0) (-6,0)
I think the process is wordy enough

In the plane rectangular coordinate system xoy, it is noted that there are three intersections between the quadratic function f (x) = x2 + 2x + B (x ∈ R) and two coordinate axes. The circle passing through the three intersections is denoted as C (1) Find the value range of real number B; (2) Find the equation of circle C; (3) Does circle C pass through a fixed point (its coordinates are independent of B)? Please prove your conclusion

(1) let x = 0, the intersection point of parabola and y-axis is (0, b); Let f (x) = x2 + 2x + B = 0, from the meaning B ≠ 0 and △ > 0, we can get B < 1 and B ≠ 0. (2) let the general equation of the circle be x2 + Y2 + DX + ey + F = 0, let y = 0 get x2 + DX + F = 0, which is the same equation as x2 + 2x + B = 0, so d = 2, f = B