What's the coefficient of the cube of four times the square of Y,

What's the coefficient of the cube of four times the square of Y,

The coefficient of the cube of - quarter x times the square of Y is - 1 / 4
The number of times is five
The square of X - 4x = 12 / 5
x²-4x=12/5
x²-4x+4=32/5
﹙x-2﹚²=32/5
∴x-2=±4/5√10
Ψ x = 2 + 4 / 5 √ 10 or x = 2-4 / 5 √ 10
-4x=12÷5
-x=12÷5÷4
-x=3÷5
x=-3/5
xx-4x=12/5
（x-2）（x-2）=12/5+4=32/5
X-2 = 4 / 5 √ 2 or X-2 = - 4 / 5 √ 2
X = 2 + 4 / 5 √ 2 or x = 2-4 / 5 √ 2
Cube of (2x) × (1 / 2 x) squared
Cube of (2x) × (1 / 2 x) squared
=8x³×1/4x²
=The fifth power of 2x
（2x）³×（x/2）²
=8x³×x²/4
=The fifth power of 2x
One
Square of (x + 1) - 4x (x + 1) + 4x
(x²+1)²-4x(x²+1)+4x²
=(x²+1)²-2×2x(x²+1)+(2x)²
=[(x²+1)-2x]²
=(x²-2x+1)²
=[(x+1)²]²
=The fourth power of (x + 1)
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Square of (x's square + 1) - 4x (x's square + 1) + 4x's Square
=(x²+1-2x)²
=[(x-1)²]²
=(x-1)^4
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Square of (x's square + 1) - 4x (x's square + 1) + 4x's Square
=(x²+1-2x)²
=[(x-1)²]²
=(x-1)^4
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You can ask if you don't understand! If you agree with my answer.
Please click the "select as satisfactory answer" button below, thank you! Put it away
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Square of (x's square + 1) - 4x (x's square + 1) + 4x's Square
=（x²+1+2x）(x²+1-2x)
=(x+1)²(x-1)²
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The function f (x) = 1 / 3 of the cube - the square of (A-1) x + the square of B, where A.B is constant
When a = 6. B = 3, find the monotone increasing interval of function f (x)
F (x) = x ^ 3 / 3 - 5x & # 178; + 9x
f'(x)＝x²-10x+9=(x-1)(x-9)
When x > 9 or X
f(x)=1/3x^3=(a-1)x^2+b^x
When a = 6. B = 3
f(x)=1/3x^3-5x^2+9x
Find the reciprocal of the first order
f(x)'=x^2-10x+9
Monotone increasing interval
therefore
f(x)'=x^2-10x+9>=0
X=9
Then f (x) = 1 / 3x ^ 3-5X & # 178; + 9x
The derivative function f '(x) = x & # 178; - 10x + 9, Let f' (x) > 0 get x < 1 or x > 9
The monotone increasing interval of ∧ f (x) is (- ∞, 1), (9, + ∞)
Decomposition factor: 4x (X-Y) quadratic + 12 (Y-X) quadratic
The power of 4x (X-Y) + the power of 12 (Y-X)
=The power of 4x (X-Y) + the power of 12 (X-Y)
=The second power of 4 (X-Y) (x + 3)
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(1 / 2x to the third power) to the second power + 3 / 4x to the square x to the fourth power - (1 / 3x to the square) to the third power
solution
(1/2x³)²+3/4x²*x^4-(1/3x²)³
=1/4x^6+3/4x^6-1/27x^6
=(1/4+3/4-1/27)x^6
=26/27x^6
The second power of 4x = 25 to find x
The absolute value of minus 3 plus the cube of minus 3 divided by the square of minus 2
(|-3|+(-3)^3)/(-2)^2 =(3+(-27))/4 = -24/4 = -6
The answer is negative 6
The absolute value of minus three is three
The minus 3 cube is - 9
Minus two squared is four
3+4/（-9）=23/9
I've forgotten it for several years after graduation, right?? It should be the main difference between division and division...
Find the solution set of inequality: - x2 + 4x + 5 < 0
∵ - x2 + 4x + 5 ＜ 0, ∵ x2-4x-5 ＞ 0, ∵ (X-5) (x + 1) ＞ 0, ∵ x ＜ - 1, or X ＞ 5, the solution set of the original inequality is {x | x ＜ - 1 or X ＞ 5}