How much is 55 For example: 55 = 44 + 1

How much is 55 For example: 55 = 44 + 1

Too many, if 54 + 1 and 1 + 54 are regarded as the same group, there are 27 groups. 54 + 1; 53 + 2; 52 + 3; 51 + 4,; 50 + 5; 49 + 6; 48 + 7; 47 + 8; 46 + 9; 45 + 10; 44 + 11; 43 + 12; 42 + 13; 41 + 14; 40 + 15; 39 + 16; 38 + 17; 37 + 18; 36 + 19; 35 + 20; 34 + 21; 33 + 22; 32 + 23
55=44+1=43+2=42+3=41+4=40+5…… =27 + 28 = 26 + 29 = 25 + 30 sum up the law, you can get all the formulas.
The integral of cosx-sinx / 1 + sinxcosx
(cosx+sinx)'=cosx-sinx
The original formula = ∫ 1 / (cosx + SiNx) d (cosx + SiNx)
=ln(cosx+sinx)+c
What's 55 plus 41
55+41=96
。。。。 96?
55+41=96!!!!
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[positive solution] 55 + 41 = 96
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96！！！！
How to find the integral of 1 / SiNx and 1 / cosx? I know the result,
∫ (1/sinx) dx
= ∫ cscx dx
= ∫ [ 1/(cscx - cotx) ]d(cscx - cotx)
=ln|cscx - cotx| + C
∫ (1/cosx) dx
= ∫ secx dx
= ∫ [ 1/(seccx + tanx) ]d(seccx + tanx)
=ln|seccx + tanx| + C
What's 55 plus 55
55+55
=55×2
=110
fifty-five plus fifty-five equals one hundred and ten
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55 plus 55 is 110
55+55
=55×2
=110
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One hundred and ten
Twenty
Let f (x) = sinx2 + cosx. (I) find the monotone interval of F (x); (II) if for any x ≥ 0, f (x) ≤ ax, find the value range of A
(1) f ′ (x) = (2 + cosx) cosx − SiNx (− SiNx) (2 + cosx) 2 = 2cosx + 1 (2 + cosx) 2. (2 points) when 2K π − 2 π 3 ＜ x ＜ 2K π + 2 π 3 (K ∈ z), cosx ＞ 12, i.e. f '(x) ＞ 0; when 2K π + 2 π 3 ＜ x ＜ 2K π + 4 π 3 (K ∈ z), cosx ＜ 12, i.e. f' (x) ＜ 0
what is fifty-five plus fifty-five
It's 110
If f (cosx + SiNx) = sinxcosx, then f (COS (π / 6)) =?
Let SiNx + cosx = t
Square 1 + 2sinxcosx = T & # 178;
sinxcosx=（t²-1）/2
f(t)=(t²-1)/2
f(cos（π/6）)=f(√3/2)=[(√3/2)²-1]/2=-1/8
(cosx + SiNx) ^ 2 = 1 + 2sinxcosx, let cosx + SiNx = t, then sinxcosx = (T ^ 2-1) / 2, so f (T) = (T ^ 2-1) / 2
When t = cos (π / 6) = √ 3 / 2, f (COS (π / 6)) = - 1 / 8
55 plus 88 plus 99 plus 10085
=10327
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Let f (SiNx + cosx) = sinxcosx, then f (COS π 6)=______ .
Let SiNx + cosx = t, we can get (SiNx + cosx) 2 = 1 + 2sinxcosx = T2, that is, sinxcosx = T2 − 12, then f (COS π 6) = f (32) = 34 − 12 = - 18