How many minutes and seconds is one degree

How many minutes and seconds is one degree

360 / 60 = 6 degrees (1 minute equals 6 degrees)
60 / 6 = 10 seconds = 1 / 6 minutes
Given the function f (x) = 2sinxcosx-2sin ^ 2x, find the maximum value of F (x) and the set of X when f (x) takes the maximum value
f(x)=2sinxcosx-2sin^2x=sin2x+cos2x-1=√2sin(2x+π/4)-1
When sin (2x + π / 4) = 1, the maximum value of F (x) = 2-1
sin(2x+π/4)=1 2x+π/4=2kπ+π/2 x=kπ+π/8 {x I x=kπ+π/8}
How many points is one degree equal to?
1 degree = 60 minutes
1 minute = 60 seconds
The maximum value of the function f (x) = 2Sin (x + π 4) + 2sinxcosx in the interval [π 4, π 2] is___ .
F (x) = 2Sin (x + π 4) + 2sinxcosx = 2Sin (x + π 4) + sin2x ∵ function y = 2Sin (x + π 4) in the interval [π 4, π 2], function y = sin2x in the interval [π 4, π 2] ∵ function f (x) = 2Sin (x + π 4) + sin2x in the interval [π 4, π 2] ∵ function f (x) ∵
How many minutes and seconds is one degree equal to
One degree = 60 minutes = 3600 seconds
Given the function f (x) = 2cos ^ 2x + 2sinxcosx-1, after simplification f (x) = √ 2Sin (2x + π / 4), find the minimum and maximum of F (x) on [0, π / 2]
F (x) = √ 2Sin (2x + π / 4) = √ 2sin2 (x + π / 8), where x is an increasing function at (- 3 π / 8, π / 8) and a decreasing function at (π / 8,5 π / 8);
When the maximum value of F (x) on [0, π / 2] is x = π / 8, then f (x) = √ 2, and the minimum value is x = π / 2, then f (x) = - 1
The minimum is. - 1. The maximum is, root 2
One degree is equal to a few minutes
How many minutes is one degree on a clock
One degree equals three minutes
Sixty minutes is 360 degrees
At one time, it's one sixth of a minute
Given the function f (x) = 2sinxcosx + 2cos ^ 2x (x belongs to R), find the minimum positive period of F (x), the minimum value and the set of X at the minimum value
Given the function f (x) = 2sinxcosx + 2cos ^ 2x (x belongs to R), find the minimum positive period of F (x), the minimum value and the set of X at the minimum value
f(x)=sin2x+cos2x-1=√2sin（2x+π/4）-1
The minimum positive period of F (x) is π
When x = 2K π + 3 / 8 π, K ∈ Z, f (x) has a minimum value of - 1 - √ 2
f(x)=sin2x+cos2x+1=√2sin(2x+π/4)+1
So the minimum positive period of F (x) is π
When 2x + π / 4 = 2K π - π / 2 (K ∈ z), that is, when x = k π - 3 π / 8 (K ∈ z), f (x) has a minimum value of 1 - √ 2
The set of X is {x | x = k π - 3 π / 8 (K ∈ z)}
2 yuan for a kilowatt hour, 10 yuan for 5 kilowatts, right? 10 yuan for 5 kilowatts, 2 yuan for a kilowatt hour, right
5*2=10
10/5=2
Isn't that right?
Given the function f (x) = 2Sin ^ 2 + sin2x-1, find the period of the function, find the maximum and minimum of the function, and find the set of X when the maximum and minimum are obtained
f(x)=2sin^2+sin2x-1
=2sin²x-1+sin2x
=-cos2x+sin2x
=√2sin(2x-π/4)
The minimum positive period of the function is 2 π / 2 = π
The maximum value of the function is √ 2 and the minimum value is - √ 2
Minimum value
2x-π/4=2kπ-π/2
x=kπ-π/8
The set of minimum x is {x | x = k π - π / 8, K ∈ Z}
At maximum
2x-π/4=2kπ+π/2
x=kπ+3π/8
When the maximum value is obtained, the set of X is {x | x = k π + 3 π / 8, K ∈ Z}