It is known that (M & # 178; - 1) x & # 178; - (m-1) x + 8 = 0 is a linear equation of one variable with respect to x, and its solution is n (1) Find the value of the algebraic formula 200 (M + n) (n-2m) - 3M + 5 (2) Find the solution of the equation m y = n about y You'd better tell me how m and N come out first!

It is known that (M & # 178; - 1) x & # 178; - (m-1) x + 8 = 0 is a linear equation of one variable with respect to x, and its solution is n (1) Find the value of the algebraic formula 200 (M + n) (n-2m) - 3M + 5 (2) Find the solution of the equation m y = n about y You'd better tell me how m and N come out first!

(1) ∵ the linear equation of one variable with respect to x,
∴m²-1=0 m-1≠0
∴m=-1
Single variable linear equation: 2x + 8 = 0
Its solution is n
∴2n+8=0
∴n=-4
The original formula = 200 (- 1-4) (- 4 + 2) + 3 + 5 = 200 × (- 5) × (- 2) + 3 + 5 = 2008
(2) Topic meaning
-|y|=-4
∴|y|=4
∴y=±4
It is known that (M 2-1) x 2 - (m-1) x + 8 = 0 is a univariate linear equation about X, and its solution is n. try to find the solution of the equation m | y | = n about y
∵ (M2-1) X2 - (m-1) x + 8 = 0 is a univariate linear equation with respect to x, M2 − 1 = 0 − (m − 1) ≠ 0, the solution is m = - 1, that is, the equation is 2x + 8 = 0, the solution is x = - 4, that is, n = - 4, substituting m | y | = n, the solution is: | y | = - 4, | y | = 4, y = ± 4, that is, the solution of the equation m | y | = n with respect to y is Y1 = 4, Y2 = - 4
How to solve the X-1 power of 2 = 128
How to solve the math problem of Grade 7; the X-1 power of 2 = 128 should be equal to 8
128＝2^7
So x = 8
The X-1 power of 2 = 128
x-1=7
X=8
I hope I can help you. Thank you
X-1 = log2 128 2 is the subscript and 128 is the superscript
We get X-1 = 7
So x = 8
1）9*5/7 - 10*2/7 + 2*19/7
2）（2009^3 - 2*2009^2 - 2007 ）/ （2009^3 - 2009^2 - 2008）
First answer, first adopt!
9*5/7 - 10*2/7 + 2*19/7=(9*5 - 10*2 + 19*2)/7=(9*5 + 2*9)/7=9*7/7=9（2009^3 - 2*2009^2 - 2007 ）/ （2009^3 - 2009^2 - 2008）=（2009^3 - 2*2009^2 - 2009 + 2 ）/ （2009^3 - 2009^2 - 2009 + 1）=（2009^3 ...
What is the 128th power of 2?
Please give the calculation process and formula
128= 2^7
2^128
=2^(2^7)
= 340282366920938463463374607431768211456
Eight mathematical factorization, 1 to 13 only write the answer, 14.15.16 only write the necessary process!
1.a^2-ab^2=
2. The common factor of a ^ 2-2ab + B ^ 2 and a ^ - B ^ 2 is -
3.4m^2+2mn+1/4n^2=
4.(2a+3b)^2=(2a-3b)^2+()
5. If (A-3) ^ 2 + B ^ 2-2b + 1=
6. Let 4x ^ 2 + MX + 49 be a complete square formula, then M=
7. If x + y = 0, xy = - 7, then x ^ 2Y + XY ^ 2=
8.20a-4a^2=
9.36m^2-25n^2=
10.y^3-2y^2+y=
11.x^2+16y^2-8xy=
12.(a^2+4a)^2+8(a^2+4a)+16=
13.(a^2+b^2)^2-4a^2b^2=
14. (A-2) (a ^ 2 + A + 1) + (a ^ 2-1) (2-A), where a = 18
15. Given a = 96, B = 92, find the value of a ^ 2-2ab-10a + 10B + 25
16. Given x + y = 5, xy = 4, find the value of x ^ 2 + y ^ 2, x ^ 4 + y ^ 4
The second power of 10000 (1-x) = 12100
(1-x)^2=121/100
1-x=11/10
x=-1/10
x^3-2x^2*y-4xy-8y-8
x3-2x²y-4xy-8y-8
=(x^3-8)-2y(x^2+2x+4)
=(x-2)(x^2+2x+4)-2y(x^2+2x+4)
=(x^2+2x+4)(x-2y-2)
x^3-2x²y-4xy-8y-8
=(x^3-8)-2y(x^2+2x+4)
=(x-2)(x^2+2x+4)-2y(x^2+2x+4)
=(x^2+2x+4)(x-2y-2)
The value of - 3 / 4 power of 10000
It's 10000 * 10000 * 10000, and then it's opened four times to 1000
It can be expressed as the reciprocal of (4 √ 10000) ^ 3 is 1 / 1000
Solving several factorization problems
1.49-x^2
2.4x^2-169y^2
3.-1+25a^2
4.0.01m^2-625n^2
5.x^2-9y^2
6.16m^2-9n^2
7.-4x^2+1
8.25(a+b)^2-9a^2b^2
9.(a+2b)^2+6(a+2b)+9
10.x^3y+2x^2y^2+xy^3
11.1/2x^2y^2+2xy+2
1.49-x^2=(7+x)(7-x)
2.4x^2-169y^2=(2x+13y)(2x-13y)
3.-1+25a^2=(5a+1)(5a-1)
4.0.01m^2-625n^2=(0.1m+25n)(0.1m-25n)
5.x^2-9y^2=(x+3y)(x-3y)
6.16m^2-9n^2=(4m+3n)(4m-3n)
7.-4x^2+1=(1+2x)(1-2x)
8.25(a+b)^2-9a^2b^2=(5(a+b)+3ab)(5(a+b)-3ab)
9.(a+2b)^2+6(a+2b)+9=(a+2b+3)^2
10.x^3y+2x^2y^2+xy^3=xy(x^2+2xy+y^2)=xy(x+y)^2
11.1/2x^2y^2+2xy+2=(x^2y^2+4xy+4)/2=(xy+2)^2/2