Given that the point a (3a, 5, - 6a-2) is on the bisector of the second and fourth quadrants, find the value of a to the power of 2009-a

Given that the point a (3a, 5, - 6a-2) is on the bisector of the second and fourth quadrants, find the value of a to the power of 2009-a

(3a, 5, - 6a-2)... Be clear
Factorization by mathematical common factor method
Example:
1.x(x-y)+y(y-x)
2.=x(x-y)-y(x-y)
3.=(x-y)(x-y)
4.=(x-y)²
In question 2, why are the X and y before the two brackets absent in question 3? The answer should be easy to understand,
2 to 3 is to extract the common factor, and the formula is AC BC = (a-b) C
therefore
2. = x (X-Y) - Y (X-Y) the common factor is (X-Y)
3.=(x-y)(x-y)
For example: ab + CB = (a + C) B
In 3, because the common factor is (X-Y), the rest is also X-Y, so the last is (X-Y) &;
The fourth power of a + the fourth power of 16b - the square of 8a and the square of B
It's factorization
The arithmetic of using denominator to express fraction in the problem of fraction
The rules of multiplication of fractions, division of fractions, addition and subtraction of fractions with the same denominator, addition and subtraction of fractions with different denominators
The multiplication rule of fraction: A / b × C / D = (a × C) / (D × d) the numerator of the product is multiplied by the numerator, and the denominator of the product is multiplied by the denominator
The division rule of fraction A / B / C / D = (A / C) / (B / D) the numerator of divisor divided by the numerator of divisor is the numerator of quotient, and the denominator of divisor divided by the denominator of divisor is the denominator of quotient
The denominator of the same denominator is the same, but the numerator is the same
Addition and subtraction of different denominator fractions: first find out the common multiple of different denominator, divide them, then multiply the numerator with the denominator by the same number, add and subtract the new numerator, and finally simplify
(the square of a - the square of 4B) (the fourth power of a - the square of 8a, the square of B + the fourth power of 16b)
There are two roads from land a to land B, each of which is 3km long. The first road is level road, the second road has 1km uphill road and 2km downhill road. Xiaogang's cycling speed on the uphill road is a kmgh, on the level road is 2 AKM / h, and on the downhill road is 3A km / h
1. When taking the second road, how long does it take for him to get from place a to place B?
2. Which way does it take him less time to go from land a to land B? How long does it take?
Q: time t = 1 / A + 2 / 3A
Question 2: the first road; t = 3 / 2A = 9 / 6A, the second road t = 5 / 3A = 10 / 6A
So the time of the first road is short, less time t = 1 / 6A
[5 / 6 + 7 / 12 / (- 3 / 2) - (- 2 / 3) / (- 5 / 36)
[5 / 6 + 7 / 12 / (- 3 / 2) - (- 2 / 3) / (- 5 / 36)
=[5/6+(7/12)×(-2/3)- 4/9] ×(-36/5)
=(5/6)×(-36/5) + (-7/18)×(-36/5) - (4/9)×(-36/5)
=-6 + 14/5 + 16/5
=-6 + 30/5
=-6+6
=0
Or:
[5 / 6 + 7 / 12 / (- 3 / 2) - (- 2 / 3) / (- 5 / 36)
=[5/6+(7/12)×(-2/3)- 4/9] /(-5/36)
=[5/6- (7/18) - 4/9] /(-5/36)
=（15/18 - 7/18 - 8/15）/(-5/36)
=0/(-5/36)
=0
A formula for the addition and subtraction of fractions
Such as the title
Be specific
(1) The formula of the same denominator addition and subtraction method is as follows:
a/c＋b/c＝(a+b)/c
a/c－b/c＝(a-b)/c
(2) The formula of different denominator addition and subtraction is as follows:
a/b＋c/d＝ad/bd＋bc/bd＝(ad+bc)/bd
a/b－c/d＝ad/bd－bc/bd＝(ad-bc)/bd
Explain the 7th power of 36-12th power of 6 with factorization
Can be divided by an integer between 64 and 72, please indicate the number
The 7th power of 36-12th power of 6
=6^14-5^12
=6^12(6^2-1)
=2^12*3^12*35
2*35=70
I think 70 should use the method of quoting factor to transform the seventh power of 36 into the fourteenth power of 6 and put forward the twelfth power of 6
The result is the 12th power of 6 multiplied by 35, which is 70
Formula deformation (fraction)
(1) E = M-A / n-a, given e, m, N, find a (give me complete steps)
(2) 1 / r = 1 / R1 + 1 / R2, given R, R1, find R2 (give me complete steps)
1)
e=m-a/n-a
en-ea=m-a
(1-e)a=m-en
a=(m-en)/(1-e) (1≠e)
2)
1/R=1/R1+1/R2
1/R2=1/R-1/R1=(R1-R)/RR1
R2=RR1/(R1-R) (R1≠R)
1）E=M-A/N-A， E-M=-A（1/N+1）， A=（M-E）/（（N+1）/N）=N（M-E）/（N+1）
2）1/R=（R1+R2）/R1R2， R=R1R2/（R1+R2）， R1R2=RR1+RR2，
R2R1-R2R=RR1
R2（R1-R）=RR1， R2=RR1/（R1-R）