已知等差數列{an}滿足an+1=an²;-nan+1,則an=______.

已知等差數列{an}滿足an+1=an²;-nan+1,則an=______.

樓主解題如下
移項有
0=an²;-nan+1-an-1
合併有
0=an²;-(n+1)an
約去an則有
0=an-(n+1)
an=n+1