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∫(4x^3-x^4)^(1/2)dx積分限2,0=∫x[(4x-x^2)^(1/2)]dx=∫x[(4-(x-2)^2]^(1/2)]dxx-2=t=∫(t+2)[(4-t^2]^(1/2)]dt積分限0,-2=∫t[(4-t^2]^(1/2)]dt+∫2[(4-t^2]^(1/2)]dt積分限0,-2第一部分好求,第二部分麻煩,用t…
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