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把我曾經答的一道題給你, ∫(e,+∞)dx/(x*(lnx)^k) =∫(e,+∞)1/(lnx)^k*d(lnx) 1.k=1 原式=ln(lnx)|(e,+∞)發散 2.k>1 原式=1/(1-k)(lnx)^(1-k)|(e,+∞) =1/(k-1)lne=1/(k-1)收斂 3.k1收斂;k
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