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設直線L1任一點座標是(x,y) 因它在直線2x+y+1=0上 所以y=-2x-1 所以那一點座標是(x,-2x-1) 設L2上的點(x',y')與那一點(x,-2x-1)關於X軸對稱, 則 x'=x y'=-(-2x-1)=2x+1=2x'+1 所以L2的函數關係式是y=2x+1
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