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方程應該是y=ax^2+bx+c的形式吧! ∵函數的開口向上 ∴a>0 二次函數的對稱軸x=-b/2a<1 即-b/2a<1 ∵2a>0,不等式兩邊同乘以2a,不等式方向不變. 得-b<2a ∴2a+b>0
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