Given the image of quadratic function as shown in the figure, find the relationship between 2A + B and 0

Given the image of quadratic function as shown in the figure, find the relationship between 2A + B and 0

The equation should be y = ax ^ 2 + BX + C!
∵ function opening up
∴a>0
The symmetry axis of quadratic function x = - B / 2A < 1
That is - B / 2A < 1
∵ 2A > 0, both sides of the inequality multiply by 2a, and the direction of the inequality remains unchanged
The results are as follows
∴2a+b>0