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f(x)=√sin²x(1-sin²x) =√sin²cos²x =|sinxcosx| =1/2|sin2x| sin2x周期は2π/2=π |sin2x|は、X軸の下にあるB x軸を180度回転させることです したがって、サイクルはsin2xの半分 T=π/2
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