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y=√1/(x²+x+1)因为x²+x+1=(x+1/2)²+3/4>0恒常的定はx²+x+1は、x=-1/2の放物線として、開口上、対称軸をX=-1/2の放物線として見ることができる(-∞,-1/2]減函数[-1/2,+∞)増函数だから、元の関数は(-∞,-1/2]増函数[-1/2,+∞)減...
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