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①∠a為頂角則∠b+∠c=180°-∠a∵∠b=∠c∴∠b=(180°-30°)/2=75°②∠a為底角,∠b也為底角則∠a=∠b=30°③∠a為底角,∠b為頂角∴∠c為底角則∠b=180°-∠a-∠c∵∠a=∠c∴∠b=180-2∠a=180°-60°=120°(本題要運用三角形的內角和等於180°,和等腰三角形底角相等的知識)
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