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若AD交於BC的線段上:有(角B為頂角) 因為角DAB=60度,又AD垂直BC,所以角ADB=90度, 得角ABD=90-60=30度,即頂角=30度. 若AD交於BC的延長線上:有(角B為頂角) 因為角DAB=60度,又AD垂直BC,所以角ADB=90度, 得角DBA為30度,頂角=180-30=150度.
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