如圖,⊙O為四邊形ABCD的外接圓,圓心O在AD上,OC‖AB.(1)求證:AC平分∠DAB;(2)若AC=8,AD:BC=5:3,試求⊙O的半徑.

如圖,⊙O為四邊形ABCD的外接圓,圓心O在AD上,OC‖AB.(1)求證:AC平分∠DAB;(2)若AC=8,AD:BC=5:3,試求⊙O的半徑.

(1)證明:∵OC‖AB∴∠OCA=∠BAC∵OA=OC∴∠OAC=∠OCA∴∠OAC=∠BAC即AC平分∠DAB;(2)∵AC平分∠DAB,∴弧CD=弧BC∴CD=BC又AD:BC=5:3∴AD:CD=5:3∵AD是圓的直徑,∴∠ACD=90°根據畢氏定理,得AD:CD:AC=5:3:4所以AD=10,即圓的半徑是5.