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用柯西不等式即可證明, 柯西不等式:(a1²;+a2²;+…+an²;)(b1²;+b2²;+…+bn²;)≥(a1b1+a2b2+…+anbn)²; 所以有(a1+a2+.+an)(1/a1+1/a2+.+1/an)≥(√1+√1+…+√1)=n²;
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