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樓上正解 y=(e^x+C)/x 常數變易法 先求xy'+y=0的解 y=C/x 設y=t(x)/x則y'=(t/x)'=(t'x+x't)/x^2代入原等式 t'=e^x 所以t=e^x+C 即xy=e^x+C
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