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答: x^3-3x^2+2 =(x^3-x^2)-2(x^2-1) =(x-1)x^2-2(x-1)(x+1) =(x-1)(x^2-2x-2) 所以: x^3-3x^2+2=0 (x-1)(x^2-2x-2)=0 解得:x=1或者x^2-2x+1=3 解得:x=1或者x=1+√3或者x=1-√3
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