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∵abc=1,∴a,b,c均不為0,則aab+a+1+bbc+b+1+cca+c+1=ac1+ac+c+bbc+b+1+bc1+bc+b=abcb+1+bc+bbc+b+1+bc1+bc+b=1+b+bcb+1+bc=1.故選A.
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