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∵sinα+sinβ=√6/3∴(sinα+sinβ)²;=(√6/3)²;=2/3∴sin²;α+2sinαsinβ+sin²;β=2/3 .(1)∵cosα+cosβ=√3/3∴(cosα+cosβ)²;=(√3/3)²;=1/3∴cos²;α+2cosαcosβ+cos²;β=…
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