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原式=[(a+1)(a+4)][(a+2)(a+3)]+1 =[(a²;+5a)+4][(a²;+5a)+6]+1 =(a²;+5a)²;+10(a²;+5a)+24+1 =(a²;+5a)²;+10(a²;+5a)+25 =(a²;+5a+5)²;
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